An even function can be reflected over the y-axis and still remain unchanged.
Example: y=x^2
On the other hand, an odd function can be reflected around the origin and also remains unchanged.
Example: y=x^3
A straightforward method to determine this is:
if f(x) is even, then f(-x)=f(x)
if f(x) is odd, then f(-x)=-f(x)
Hence, for an even function
substitute -x in for each and check for equivalence
make sure to fully expand the expressions
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original expression
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
Not the same, as the original contains -2x
Therefore, it is not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
It matches, hence it is even
g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
Not equivalent, thus not even
g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
Not equal, therefore not even
g(x)=2x²+1 is the confirmed even function.
Answer:

Step-by-step explanation:

The given formula doesn't appear to match any of the answer choices.
W = (P/2) - L
The function is applicable within the segments of x:
(-∞, -1) and [-1, 7), meaning it is valid for x < 7.
Importantly,
the function cannot be evaluated at x = -1 in the left part of the linear graph, while it is valid at x = -1 in the right segment of the same line. Additionally, the function is not defined at x = 7 or any value above it.
Conclusion: x < 7.
Answer:
a) Ann has a 1/3 chance of winning in the first round
b) The chance of Ann winning for the first time in the fourth round is 8/81
c) The probability that Ann's first win occurs after the fourth round is 16/81
Step-by-step explanation:
a) Each strategy is played with a probability of 1/3. Given any strategy, there’s a 1/3 chance that Bill will choose the strategy that allows Ann to win. Consequently, the probability of Ann securing a victory in the first round (or any round) is
1/3 * 1/3 + 1/3 * 1/3 + 1/3 * 1/3 = 1/9 + 1/9 + 1/9 = 1/3.
Thus, the likelihood of Ann winning the initial round is 1/3.
b) The chances of Ann winning a round stand at 1/3; therefore, her chances of not winning are 2/3. This must happen three times before her first victory. Thus, the probability that Ann's first win occurs in the fourth round is
(2/3)³ * 1/3 = 8/81.
c) The first victory happens after the fourth round if she remains unsuccessful in the first four rounds, translating to a possibility of (2/3)⁴ = 16/81.
The result I found is 32.761%. Percentage represents any fraction expressed out of 100. It's calculated using the formula: If A is to be expressed as a percentage of B, the formula is A/B * 100. In this case, the paid price for the sweater is $36.20 and the original price is $90.50. We endeavor to find out what percentage reflects the sale price of the sweater. Mathematically, this can be framed as what is 36.20% of 90.5, which translates to (price paid/original price) * 100, and mathematically results in ($36.20/$90.50) * 100 = 32.761. Thus, this indicates that the sweater was sold for 32.761% off its original price.