The revenue of Apple® went from $54.5 billion in 2013 to $74.6 billion1 in 2015. Find an exponential function to model the reven

Answer: The mean and variance of Y are $0.25 and $6.19 respectively.

Step-by-step explanation:

The scenario is as follows: You and a friend participate in a game involving tossing a fair coin.

The sample space for tossing two coins is {TT, HT, TH, HH}

Let Y represent the earnings from one round of the game.

If both faces are heads, you win $1; therefore, P(Y=1)=P(TT)=

You win $6 if both faces are heads, so P(Y=6)=P(HH)=

If the faces do not match, you lose $3 which means P(Y=1)=P(TH, HT)=

To find the expected value to win: E(Y)=

Thus, the mean of Y: E(Y)= $0.25

Variance =

Therefore, variance of Y = $ 6.19

Answer:

The segments of the positive graph are located at the coordinates (-5,-4) and (2,5).

In contrast, the negative segment is identified as (-4,2).

Step-by-step explanation:

The positive graph is above the x-axis, while the negative portion lies beneath the y-axis.

Within the interval (-1,5),

The graph appears below the x-axis between (-1,2)

And above it between (2,5).

At this juncture, Lonzell’s assertion is inaccurate.

Within the interval (-5,-1),

The graph again resides below the x-axis in the range (-4,-1)

And above it between (-5,4).

At this point, Lonzell's assessment remains incorrect.

Thus,

The segments of the positive graph are at the coordinates (-5,-4) and (2,5).

Meanwhile, the negative segment is identified at (-4,2).

Answer:

40 * x - 600 = 0

Step-by-step explanation:

Initially, identify the variable (x) in the equation, representing the number of days it takes Leilah to review her flashcards. To study 600 out of her 2400 cards, having gone through 1800 already, we arrive at:

2400 - 1800 = 40 * x

rearranging leads to

40 * x - 600 = 0

This equation describes the situation above

The pairs that have an HCF of 3 and an LCM of 45 are (3,45) and (15,9).

A matching complex for 2+3i is required. The conjugate is 2-3i, leading to the factors (x-2-3i)(x-2+3i)=(x²-4x+4+9)=x²-4x+13. The resulting polynomial is (x-4)(x+8)(x²-4x+13)=(x²+4x-32)(x²-4x+13)=x⁴-4x³+13x²+4x³-16x²+52x-32x²+128x-416, resulting in the 4th degree polynomial: x⁴-35x²+180x-416.