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givi
11 days ago
11

Ruben bought 6 new books for his collection. This increased his collection by 12%. How many books did he have before his purchas

es?
Mathematics
1 answer:
tester [8.8K]11 days ago
4 0

Response: Ruben initially possessed 50 books before making any purchases.

Explanation in steps: Ruben's acquisition of 6 new books led to a 12% increase in his collection.

We aim to determine the quantity of books Ruben had prior to his recent purchases.

Let x represent the original count of books Ruben held before buying more.

Based on the provided data, we derive the following equation:

x+6=x+12\%\times x\\\\\\\Rightarrow 6=\dfrac{12}{100}x\\\\\\\Rightarrow 6=\dfrac{3x}{25}\\\\\\\Rightarrow 3x=150\\\\\Rightarrow x=\dfrac{150}{3}\\\\\Rightarrow x=50.

Consequently, the original number of books Ruben had before making additional purchases equals 50.

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Which graph represents an odd function?<br><br>Answer by using: A, B, C, or D for each graph.
AnnZ [9104]

Answer: Option C is the correct graph.

Explanation:

An odd function satisfies the condition,

f(-x)=-f(x)

This indicates that for any point (x,y) on the graph, the point (-x,-y) will also be present.

Why Option C is correct:

Option C includes the point (1,2), which implies the point (-1,-2) must be present.

f(1)=2

Indeed, (-1,-2) is among the points.

f(-1)=-f(1)=-2

Other pairs like (2,3) with (-2,-3), (3,-1) with (-3,1), and (4,0) with (-4,0) are also found. Hence, the function represented is odd.

Why other options are incorrect:

In Option A, (1,3) is given, so at x = -1, y should be -3, but instead y = 1, so it’s not odd.

Option B has (1,0), so at x = -1, y should be 0, but y = -3, so it is not odd.

Option D features (1,-1), meaning at x = -1 y should be 1; however, y = -1, so it's not odd.

6 0
1 month ago
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If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50
lawyer [9240]
We can apply the formula to tackle this problem, utilizing the following variables: R represents the rate, W signifies the workers/things, T stands for time, and J indicates the jobs/things. In the scenario where 10 printers print 10 pages within 10 seconds, we identify W as 10 printers, T as 10 seconds, and J as 10 pages. Thus, we can deduce how many seconds it will take for 50 printers to produce 50 pages. Based on the previous findings, we can determine T. Ultimately, it will still take 10 seconds for 50 printers to print 50 pages.
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14 days ago
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Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random
zzz [9093]

Answer:

0.64 ± 0.1117 or

0.64\pm 1.645*\sqrt{\frac{0.64*(0.36)}{50}}

Step-by-step explanation:

Sample size (n) = 50

Z-score for a 90% confidence level (z) = 1.645

Proportion of students who read at least one book (p):

p=\frac{32}{50}=0.64

The confidence interval is calculated as:

p\pm z*\sqrt{\frac{p*(1-p)}{n} }

By applying the provided information:

0.64\pm 1.645*\sqrt{\frac{0.64*(1-0.64)}{50}}\\ 0.64\pm 0.1117

The confidence interval results in 0.64 ± 0.1117

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28 days ago
The annual net income of a company for the period 2007–2011 could be approximated by P(t) = 1.6t2 − 11t + 44 billion dollars (2
babunello [8423]

Answer:

P'(t) = 3.2 t -11

To identify the critical point, we set the derivative equal to zero, resulting in:

3.2 t-11= 0

t = \frac{11}{3.2}= 3.4375

Calculating the second derivative yields:

P''(t) = 3.2 >0

This indicates that t = 3.4375 marks the minimum value for the function. Substituting this back into the original function gives us:

P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094

Thus, the minimum annual income is found at t = 3.43 (between the years 2008 and 2009), with a value of 25.094

Step-by-step explanation:

In this scenario, we have the function:

P(t) = 1.6 t^2 -11t +44

Where P represents the annual net income from 2007-2011, and 2 \leq t \leq 7

t is the number of years since early 2005

To discover the lowest income, we utilize the derivative given by:

P'(t) = 3.2 t -11

Setting this derivative to zero allows us to find the critical point, leading to:

3.2 t-11= 0

t = \frac{11}{3.2}= 3.4375

Calculating the second derivative reveals:

P''(t) = 3.2 >0

Therefore, we conclude that t = 3.4375 is the minimum value, substituting into the original function results in:

P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094

Thus, the minimum annual income occurs at t = 3.43 (between 2008 and 2009) with the value being 25.094

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5 days ago
A line contains (34,12) and (32,48) what is the slope of the line in simplified form? HELP ASAPl
Zina [9179]

Response:

m=-18

Step-by-step explanation:

1. The line includes the points (34,12) and (32,48). Then, apply the slope formula, which is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

2. By substituting values into the formula, you will get:

y_{2}=48\\y_{1}=12\\x_{2}=32\\x_{1}=34

m=\frac{48-12}{32-34}\\m=\frac{36}{-2}\\m=-18

4 0
9 days ago
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