A child rides a pony on a circular track whose radius is 5.25 m. a) Find the distance traveled and the displacement after the ch

In this situation, we start with the following equation: To isolate the value of y, we follow these steps: First, we subtract 6 from both sides of the equation: Second, we take away "y" from each side: Third, we add to both sides of the equation: Finally, we divide the equation by 4. Thus, y equals 5. Answer: Option C.

I estimate that a total of 50 students participated in the survey

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Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4  <<< Answer

Hello! You need to calculate a 99% confidence interval for the difference in mean lifespan between two tire brands. Each tested car was assigned one tire from each brand randomly on the rear wheels, allowing for paired sample analysis.       Brand 1  Brand 2  X₁-X₂      car 1:  36,925;  34,318;  2.607      car 2:  45,300;  42,280;  3.020      car 3:  36,240;  35,500;  0.740      car 4:  32,100;  31,950;  0.150      car 5:  37,210;  38,015;  -0.0805      car 6:  48,360;  47,800;  1.160      car 7:  38,200;  37,810;  0.390      car 8:  33,500;  33,215;  0.285      n= 8 The study variable is defined as Xd= X₁-X₂, where X₁ represents the tire lifespan (in km) from Brand 1 and X₂ represents Brand 2. Thus, Xd is the difference in tire lifespan. Xd~N(μd;δd²) (normality test p-value is 0.4640). For calculating the confidence interval, the best statistic is the Student's t using the following formula: t= (xd[bar] - μd)/(Sd/√n) ~t₍ₙ₋₁₎ sample mean: xd[bar]= 0.94 standard deviation: Sd= 1.29 = 3.355 xd[bar] ± *(Sd/√n) ⇒ 0.94 ± 3.355*(1.29/√8) [-0.65;2.54]km. The CI can be compared to bilateral hypothesis testing: H₀:μd=0 H₁:μd≠0 using significance level of 0.01. Since the confidence interval includes zero, we do not reject the null hypothesis, indicating no significant difference between the tire brands. Hope you have a fantastic day!

The graph indicates that x never goes below 0. This means the point (-1,0) is not included in the graph. Therefore, D is the only valid option.