Response:
C++ code provided below with suitable annotations
Clarification:
pattern.cpp
#include<iostream>
using namespace std;
void printCross(int n)
{
int i,j,k;
if(n%2) //odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i || j==(n-i+1))
cout<<j;
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i || j==(n-i+1))
{
cout<<" "<<j<<" ";
}
else
cout<<" ";
}
cout<<"\n";
}
}
void printForwardSlash(int n)
{
if(n%2)
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==n-i+1)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==(n-i+1))
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
void printBackwardSlash(int n)
{
if(n%2) // odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
int main()
{
int num;
char ch;
cout<<"Create a numberes shape that can be sized."<<endl;
cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;
cin>>num>>ch;
if(ch=='x' || ch=='X')
printCross(num);
else if(ch=='f' || ch=='F')
printForwardSlash(num);
else if(ch=='b' || ch=='B')
printBackwardSlash(num);
else
cout<<"\nWrong input"<<endl;
return 0;
}
Hello <span>Miyalashay8283
</span>
Question: <span>When your computer runs out of ram, the operating system borrows space from the cpu.
Answer: This statement is untrue.
I hope this information is useful
-Chris</span>
#include <iostream>
using namespace std;
void OutputMinutesAsHours(double origMinutes) {
double hours = origMinutes / 60.0;
cout << hours;
}
int main() {
OutputMinutesAsHours(210.0); // This function will also be called with 3600.0 and 0.0.
cout << endl;
return 0;
}
The lines highlighted in bold perform the conversion from minutes to hours by dividing the input minutes by 60, since there are 60 minutes in one hour. The parameter origMinutes is a double, so the division uses 60.0 to keep consistent data types. Running this code with 210.0 will output 3.5.
Response:
No.
Clarification:
Since there are 5 vowels, at least 3 bits are necessary to represent them all. Utilizing 2 bits yields 2²=4 combinations, which isn’t enough. However, using 3 bits provides 2³=8 combinations, sufficiently covering the 5 vowels.
