The engineering firm you work for is submitting a proposal to create an amphitheater at a state park. Proposals must be submitte
1 answer:
You might be interested in
Answer:
#SECTION 1
while True:
month = input("Input the month (e.g. January, February etc.): ")
try:
if month in ('January', 'February', 'March','April', 'May', 'June','July', 'August', 'September', 'October', 'November', 'December'):
day = int(input("Input the day: "))
try:
if day > 31:
raise
elif day == 31 and month in ('September', 'April', 'June', 'November'):
raise
elif day > 29 and month == 'February':
raise
else:
break
except:
print('Invalid!!!')
print('Day not correct')
else:
raise
except:
print('Invalid!!!')
print('Enter correct Month')
#SECTION 2
if month in ('January', 'February', 'March'):
season = 'winter'
elif month in ('April', 'May', 'June'):
season = 'spring'
elif month in ('July', 'August', 'September'):
season = 'summer'
else:
season = 'autumn'
if (month == 'March') and (day > 19):
season = 'spring'
elif (month == 'June') and (day > 20):
season = 'summer'
elif (month == 'September') and (day > 21):
season = 'autumn'
elif (month == 'December') and (day > 20):
season = 'winter'
print("Season is", season)
Explanation:
#SECTION 1
This section is designed to ensure that the user inputs a valid month and day. The try and except blocks paired with IF statements work together to achieve accurate results. The while loop continues until a legitimate input is received.
The first try block checks if the month provided exists by comparing it against a predefined list. If it fails, an error is raised, triggering the except block that informs the user of the invalid entry.
When the first TRY block succeeds, it moves to the next stage, which takes a number input, confirming that it is correct for each month. Any invalid input leads to an error, stimulating the try block to print the issue.
If all inputs are valid, the program exits the loop and transitions to the subsequent section.
#SECTION 2
This part uses the given data to determine the season, leveraging IF statements to produce the result, which it then prints.
I have attached a sample for you to see how the code operates using both incorrect and correct input values.
Answer:
alphabet = "abcdefghijklmnopqrstuvwxyz"
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]
# From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press.
def histogram(s):
d = dict()
for c in s:
if c not in d:
d[c] = 1
else:
d[c] += 1
return d
#Part 1 Construct a function, called has_duplicates, that takes a string argument and returns True if there are any repeating characters present. If not, it should return False.
def has_duplicates(stringP):
dic = histogram(stringP)
for key,value in dic.items():
if value>1:
return True
return False
# Execute has_duplicates by building a histogram using the above histogram function. Implement a loop over the items in the test_dups list.
# Display each string and indicate whether it has duplicates based on the has_duplicates function's result for that string.
# For instance, the expected output for "aaa" and "abc" would be shown below. aaa has duplicates abc has no duplicates Display a similar message for each string within test_dups.
print("***Implementation of has_duplicates function***")
for sTr in test_dups:
if has_duplicates(sTr):
print(sTr+": has duplicates")
else:
print(sTr+": has no duplicates")
#Part 2 Develop a function named missing_letters that takes a string argument and returns a new string containing all alphabet letters absent from the input string.
#The letters in the resultant string should be arranged in alphabetical order. Your implementation must utilize the histogram from the previous function and should reference the global alphabet variable directly.
#It should iterate over the alphabet letters to figure out which are missing from the input string.
#The function missing_letters should merge the list of missing letters into a string and return it.
def missing_letters(sTr):
missingLettersList = []
dic = histogram(sTr)
for l in alphabet:
if l not in dic:
missingLettersList.append(l)
missingLettersList.sort()
return "".join(missingLettersList)
#Iterate over the strings in the test_miss list and invoke missing_letters for each one. Present a line for each string outlining the missing letters.
#For example, for the string "aaa", the output should be as follows. aaa is missing letters bcdefghijklmnopqrstuvwxyz
#Should the string encompass all alphabet letters, the output should indicate that it utilizes all the letters.
#For instance, output for the alphabet string itself would be: abcdefghijklmnopqrstuvwxyz uses all the letters
#Generate a similar line for each item in test_miss.
print("\n***Implementation of missing_letters function***")
for lTm in test_miss:
sTr = missing_letters(lTm.replace(" ",""))
if sTr!="":
print(lTm+" is missing letters "+sTr)
else:
print(lTm +" uses all the letters")
