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Furkat
7 days ago
12

What proportion of these candy bars have more than 300 calories per serving? (Round your answer to two decimal places.)

Mathematics
1 answer:
Inessa [3.9K]7 days ago
3 0

Answer: 0.12

Step-by-step explanation:

There are a total of 65 candy bars. Within this amount;

2 candy bars contain 300 to 350 calories

1 candy bar contains 350 to 400 calories

4 candy bars contain 400 to 450 calories

1 candy bar contains 450 to 500 calories

Thus, the overall ratio of candy bars with more than 300 calories is;

= (2 + 1 + 4 + 1) / 65

= 8/65

= 0.12

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13 days ago
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The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a
Leona [4187]

Answer:

The range of cheerleaders' heights lies within the interval [58, 74)

It includes all real numbers from 58 inches and above, but below 74 inches.

Step-by-step explanation:

we have

260 \leq 4h+28

Separate the combined inequality into two distinct inequalities

260 \leq 4h+28 -----> inequality A

4h+28 -----> inequality B

Solve inequality A

260 \leq 4h+28

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232 \leq 4h

Split by 4 on both sides

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Reformulate

h \geq 58\ in

Address inequality B

4h+28

Subtract 28 from both sides

4h

Split by 4 on both sides

h

consequently

The height range of the cheerleaders is the interval [58, 74)

It consists of every real number starting from 58 inches and less than 74 inches

3 0
6 days ago
John needs 13 bottles of water from the store. john can only carry 3 at a time. what's the minimum number of trips john needs to
Inessa [3926]
The smallest number of trips he must make is 5. Since he can carry only 3 bottles per trip, 5 trips would allow him to transport 15 bottles.
Though it might seem like 4 trips could suffice, as 4 times 3 is 12, that's one bottle short of 13.
Hence, an additional trip is needed to carry the last bottle, totaling 5 trips.
4 0
13 days ago
Find x if a =13 and C = 47 need help
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You can utilize the Pythagorean theorem expressed as a^2 + b^2 = c^2... if b is unknown, you can rearrange the formula. Hence, c^2 - a^2 = b^2. Squaring 47 gives 2209 and squaring 13 yields 169... Subtracting gives you 2209-169, which results in 2040. Taking the square root of that yields approximately 45.166359, which can be rounded to 45 or as 45.167 when expressed to two decimal places. I hope this helps!:)

7 0
12 days ago
Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
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The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
5 0
14 days ago
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