Step-by-step explanation:
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Answer:
The range of cheerleaders' heights lies within the interval [58, 74)
It includes all real numbers from 58 inches and above, but below 74 inches.
Step-by-step explanation:
we have

Separate the combined inequality into two distinct inequalities
-----> inequality A
-----> inequality B
Solve inequality A

Subtract 28 from both sides

Split by 4 on both sides

Reformulate

Address inequality B

Subtract 28 from both sides

Split by 4 on both sides

consequently
The height range of the cheerleaders is the interval [58, 74)
It consists of every real number starting from 58 inches and less than 74 inches
The smallest number of trips he must make is 5. Since he can carry only 3 bottles per trip, 5 trips would allow him to transport 15 bottles.
Though it might seem like 4 trips could suffice, as 4 times 3 is 12, that's one bottle short of 13.
Hence, an additional trip is needed to carry the last bottle, totaling 5 trips.
You can utilize the Pythagorean theorem expressed as a^2 + b^2 = c^2... if b is unknown, you can rearrange the formula. Hence, c^2 - a^2 = b^2. Squaring 47 gives 2209 and squaring 13 yields 169... Subtracting gives you 2209-169, which results in 2040. Taking the square root of that yields approximately 45.166359, which can be rounded to 45 or as 45.167 when expressed to two decimal places. I hope this helps!:)
The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.
For m₁: m₁*g - T = m₁*a
For m₂: T - m₂*g = m₂*a
Assuming a massless cord and pulley without friction, the accelerations are the same.
From the second equation: a = (T - m₂*g) / m₂
Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g
This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>