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15 days ago

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Vijay owns a house worth $250,000 with a mortgage of $150,000. He has $3,000 in stock investments and $1,700 in a checking accou

nt. He owns a piano worth $1,800. He also owns a car worth $18,000 and owes $6,000 in car loans. Vijay wants to create a net worth statement. What are Vijay’s total assets, liabilities, and net worth? :v

1 answer:

lawyer [4K]15 days ago

7 0

Answer:

Total assets amount to $274,500

Total liabilities stand at $156,000

Thus, net worth equals $118,500

Step-by-step explanation:

Vijay’s assets include his house, stock investments, checking account balance, piano, and car.

Total assets=$250,000+$3,000+$1,700+$1,800+$18,000=$ 274,500.00

Vijay’s liabilities consist of debts owed to others, including the mortgage and car loans.

Total liabilities=$150,000+$6,000=$156,000

Net worth is calculated as total assets minus total liabilities=$274,500-$156,000=$118,500.00

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When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t

zzz [4022]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

$\boxed{u \ or \ v_i = initial \ velocity}$

$\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}$

$\boxed{a = acceleration \ (constant)}$

$\boxed{d = distance \ travelled}$

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

$\boxed{ \ v^2 = u^2 + 2ad \ }$

a = acceleration (m/s²)
u = initial speed = 0 m/s
v = takeoff velocity = 1.0 m/s
d = displacement = 0.50 mm

First, convert 0.50 mm to meters: $\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}$

Solution steps:

Rearrange the formula to isolate acceleration (a).

$\boxed{ \ v^2 = u^2 + 2ad \ }$

$\boxed{ \ v^2 - u^2 = 2ad \ }$

$\boxed{ \ 2ad = v^2 - u^2 \ }$

$\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }$

Insert the given values into the rearranged equation.

$\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }$

$\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }$

$\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }$

$\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }$

This yields the flea's acceleration as 1,000 m/s².

Additional resources

Scientific notation: brainly.com/question/7263463
Determining substance mass: brainly.com/question/4053884
Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

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14 days ago

Read 2 more answers

A box has 14 camera of which 6 are refurbished and 8 are new. If four of these 14 cameras are selected at random without replace

Leona [4166]

Answer:

160/1001, 175/1001

Step-by-step explanation:

i) We calculate:

₈C₁ methods to select 1 new camera from a selection of 8

₆C₃ methods to select 3 refurbished cameras from a selection of 8

₁₄C₄ methods to select 4 cameras from the total of 14 cameras

The probability formula is:

P = ₈C₁ ₆C₃ / ₁₄C₄

P = 8×20 / 1001

P = 160 / 1001

P ≈ 0.160

ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:

P = ₆C₄ / ₁₄C₄

P = 15 / 1001

Therefore, the combined probability is:

P = 160/1001 + 15/1001

P = 175/1001

P ≈ 0.175

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10 days ago

Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month

AnnZ [3877]

Answer:

a) The first inequality is 100 + 55x > 150 + 51x;

b) The final inequality results in x > 12.5

c) Sal's mother will need to use the second phone for at least 13 months.

Step-by-step explanation:

a) Let x represent the number of months.

1. The first phone is priced at $100, with a monthly fee of $55 for unlimited use, leading to a total cost of $(100 + 55x) for x months.

2. The second phone costs $150 with a monthly fee of $51 for unlimited use, resulting in a total of $(150 + 51x) for x months.

3. For the second phone to be cheaper, we set up the inequality:

150 + 51x < 100 + 55x

which simplifies to

100 + 55x > 150 + 51x

b) Now solve this:

55x - 51x > 150 - 100

4x > 50

so x > 12.5

c) This means Sal's mother has to retain the second phone for at least 13 months (since x > 12.5).

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12 days ago

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A waterbed filled with water has the dimensions 8ft by 7 ft by .75 ft taking the density of water to be 1.00/gm cubed how many k

Svet_ta [4321]

Density can be defined as:

$D = \frac{m}{V}$

Where:

m is mass

V stands for volume

To isolate the mass, we derive:

$m = DV$

Volume can be expressed as:

$V = (8) * (7) * (0.75)$

$V = 42ft ^ 3$

We then use the following conversion:

$1foot = 0.3048m$

After applying the conversion, we arrive at:

$V = 42 * (0.3048) ^ 3$

$V = 1.19m ^ 3$

Additionally, we have these conversions:

$1m = 100cm$

$1Kg = 1000g$

When we apply these conversions for density, we conclude:

$D = (1\frac{g}{cm^3})((\frac{100}{1})^3\frac{cm^3}{1m^3})(\frac{1}{1000}\frac{Kg}{g})=1000\frac{Kg}{m^3}$

Finally, the mass of the water required is:

$m = (1000) * (1.19)$

$m = 1190$

Answer:

A total of 1190 kilograms of water is needed to fill the waterbed.

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6 days ago

A salesperson has to drive 500 miles. For the first three hours she drove at 65 mi/h. For the next two hours she drove at 55 mil

AnnZ [3877]

Short answer: 195
First, you multiply 65 by 3, yielding 195 miles.
Then, multiplying 55 by 2 gives you 110 miles.

By summing both distances, you arrive at 305.
From 500, if you subtract 305, you find =195.

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1 day ago