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I am Lyosha
2 months ago
12

Declare a constant named YEAR, and initialize YEAR with the value 2050. Edit the statement myNewAge = myCurrentAge + (2050 − cur

rentYear) so it uses the constant named YEAR. Edit the statement cout << "I will be " << myNewAge << " in 2050." << endl; so it uses the constant named YEAR.#include
using namespace std;
int main()
{
int myCurrentAge = 29;
int myNewAge;
int currentYear = 2014;


myNewAge = myCurrentAge + (2050 - currentYear);

cout << "My Current Age is " << myCurrentAge << endl;
cout << "I will be " << myNewAge << " in 2050." << endl;

return 0;
}
looking for code pattern
Computers and Technology
1 answer:
amid [951]2 months ago
7 0

Answer:

The following changes will be implemented to the source code

const int YEAR = 2050;

cout << "I will be " << myNewAge << " in "<<YEAR<<"." << endl;

Explanation:

First, YEAR needs to be defined as a constant integer. This is represented as follows;

const int YEAR = 2050;

This allows us to refer to YEAR throughout the program

Next,

Substitute the following:

cout << "I will be " << myNewAge << " in 2050." << endl;

with

cout << "I will be " << myNewAge << " in "<<YEAR<<"." << endl;

The revised source file is attached;

Download cpp
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Answer:

Below is the explanation for the C code.

Explanation:

#include <stdio.h>

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Read 2 more answers
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