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algol13
3 months ago
12

What happened if the offshore team members are not able to participate in the iterations demo due to timezone/infrastructure iss

ues?
a) No issues. Onsite members can have the iteration demo with the product owner; it a single team anyway.



b) Offshore members will miss the opportunity to interact with product owner and get the direct feedback about the increment they created.



c) No Major issue. Since offshore lead and onsite members participate in the demo with the product owner, they can cascade the feedback back to the offshore members.



d) It is a loss as the offshore members will not be able to contribute to the ideas releated way of working
Computers and Technology
1 answer:
zubka84 [1K]3 months ago
4 0

What if the offshore team members are unable to join the iterations demonstration because of timezone or infrastructure issues? (c) Not a significant problem. The offshore lead and the onsite team members will attend the demo with the product owner and can relay the feedback to the offshore team afterwards.

Explanation:

Not a significant problem. The offshore lead and the onsite team members will attend the demo with the product owner and can relay the feedback to the offshore team afterwards.

From the previous statement, it is evident that if offshore team members cannot attend the demo alongside the product owner due to issues with time zones or infrastructure, it won't pose a major concern because the onsite team will be present and can share all relevant insights and feedback with the offshore team. They all belong to the same team.

Therefore, the answer (3) is correct

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This program will calculate the rise in ocean levels over 5, 10, and 50 years, Part of the program has been written for you. The
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Answer:

Here is the C++ code:

#include <iostream> //for utilizing input and output functions

using namespace std; //for defining objects cin cout

int main(){ //beginning of the main function

     

   double risingLevel; //declares a variable of type double to store the rising level

   cin>>risingLevel; //captures the risingLevel input from the user

   

   cout<<"Level: "<<risingLevel<<endl; //outputs the rising level

   cout << "Years: 5, Rise: " << risingLevel * 5<<endl; //outputs the increase in ocean level over 5 years

   cout << "Years: 10, Rise: " << risingLevel * 10<<endl; //outputs the increase in ocean level over 10 years

   cout << "Years: 50, Rise: " << risingLevel * 50<<endl; //outputs the increase in ocean level over 50 years

}

Explanation:

The functioning of the program is as follows:

Supposing the user inputs a rising level of 2.1, then,

risingLevel = 2.1

At that point, the first print statement (cout):

cout<<"Level: "<<risingLevel<<endl; outputs the value of risingLevel to the display. Therefore, this line shows:

Level: 2.1

Next, the program proceeds to the following statement:

   cout << "Years: 5, Rise: " << risingLevel * 5<<endl;

which calculates the increase in ocean levels for a duration of 5 years using the equation:

risingLevel * 5 = 2.1 * 5 = 10.5

It subsequently shows the calculated result on the display. So, this line shows:

Years: 5, Rise: 10.5 Then, the control shifts to the next statement:

   cout << "Years: 10, Rise: " << risingLevel * 10<<endl;

that computes the rise in ocean levels over a span of 10 years using the equation:

risingLevel * 10 = 2.1 * 10 = 21

It then showcases the calculated figure on the output screen. Thus, the output is:

Years: 10, Rise: 21

Next, the program control progresses to this statement:

   cout << "Years: 50, Rise: " << risingLevel * 50<<endl;

which determines the rise in ocean levels for a duration of 50 years using the equation:

risingLevel * 50 = 2.1 * 50 = 105

This then displays the computed result on the output screen, leading to the output:

Years: 50, Rise: 105 Consequently, the complete output from the program will be:

Level: 2.1 Years: 5, Rise: 10.5

Years: 10, Rise: 21

Years: 50, Rise: 105

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Answer:

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Answer:

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