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algol13
1 month ago
12

What happened if the offshore team members are not able to participate in the iterations demo due to timezone/infrastructure iss

ues?
a) No issues. Onsite members can have the iteration demo with the product owner; it a single team anyway.



b) Offshore members will miss the opportunity to interact with product owner and get the direct feedback about the increment they created.



c) No Major issue. Since offshore lead and onsite members participate in the demo with the product owner, they can cascade the feedback back to the offshore members.



d) It is a loss as the offshore members will not be able to contribute to the ideas releated way of working
Computers and Technology
1 answer:
zubka84 [942]1 month ago
4 0

What if the offshore team members are unable to join the iterations demonstration because of timezone or infrastructure issues? (c) Not a significant problem. The offshore lead and the onsite team members will attend the demo with the product owner and can relay the feedback to the offshore team afterwards.

Explanation:

Not a significant problem. The offshore lead and the onsite team members will attend the demo with the product owner and can relay the feedback to the offshore team afterwards.

From the previous statement, it is evident that if offshore team members cannot attend the demo alongside the product owner due to issues with time zones or infrastructure, it won't pose a major concern because the onsite team will be present and can share all relevant insights and feedback with the offshore team. They all belong to the same team.

Therefore, the answer (3) is correct

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Write an application that throws and catches an ArithmeticException when you attempt to take the square root of a negative value
Harlamova29_29 [932]

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

   public static void main(String[] args) {

       double number;

       double squareRootOfNumber;

       String userInput = null;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Please enter a number: ");

       userInput = scanner.next();

       number = Double.parseDouble(userInput);

       squareRootOfNumber = Math.sqrt(number);

       if (number < 0) {

           throw new ArithmeticException("Cannot compute the square root of a negative number");

       }

       System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

   }

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");

3 0
1 month ago
Write a method, isEmailAddress, that is passed a String argument. It returns true or false depending on whether the argument has
Amiraneli [921]

Answer:

//This method takes a parameter called myString of type String

public static boolean isEmailAddress (String myString){

//verifying if the @ character exists in the string

if (myString.indexOf("@")!= -1) {

  //ensuring that only a single instance of @ appears in the string

   if (myString.indexOf("@") == myString.lastIndexOf("@")) {

   //confirming absence of space characters

  if (myString.indexOf(" ") == -1) {

    //checking for the absence of newline characters in the string

    if (myString.indexOf("\n") == -1) {

      //checking for absence of tab characters in the string

      if (myString.indexOf("\t") == -1) {

          return true;

      }

    }

  }

}

}

 return false;

}

Explanation:

The method takes a string presumed to be an email address and verifies whether it is valid, returning true if it is valid and false otherwise. The method checks the following conditions:

->The presence of the "@" character

->Only one occurrence of "@" exists in the string

->No spaces present

->No newline characters present

->No tab characters present

Returning true only if all these conditions are met.

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Harlamova29_29 [932]

Answer:

A

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For years, there were minimal modifications to the fundamental internet protocols; HTTP saw the addition of some new headers and methods, TLS underwent gradual updates, TCP improved congestion management, and DNS incorporated features like DNSSEC. Over a lengthy period, these protocols remained consistent as seen on the wire — with the exception of IPv6, which is regularly discussed among network operators.

Consequently, network administrators, vendors, and policymakers seeking to understand (and sometimes regulate) the Internet have implemented various practices based on the protocols’ wire ‘footprint’ — whether to troubleshoot issues, enhance service quality, or enforce policies.

Currently, there are considerable changes happening in core internet protocols. Although these updates aim to remain compatible with the wider Internet to ensure adoption, they might disrupt entities that have exploited undocumented features of existing protocols or assumed stability in certain aspects.

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Natasha_Volkova [897]

Answer:

import random

random.seed(1,10) # Note: seed takes one argument, so this line has an error

a = random.randint(1, 10)

b = random.randint(1, 10)

print("Calculate: " + str(a) + " X " + str(b) + "?")

ans = int(input("Your answer: "))

if ans == a * b:

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Explanation:

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8_murik_8 [892]

Answer:

Below is the Python code:

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Explanation:

The logic behind the program is clearly outlined in the attached comments. To illustrate the program's workings, let's consider an example:

Imagine the user inputs the stock_prices values of

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The input() method captures user input, while the split() method divides the input string, providing a list of strings as:

['34.62', '76.30', '85.05']

Following that, the loop statement for price in stock_prices: iterates through each item in the list, and print("$",price) displays each value from the list on the output screen with a dollar sign, as follows:

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