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Evgen
6 days ago
10

Identify the range of the function shown in the graph

Mathematics
2 answers:
PIT_PIT [3.9K]6 days ago
8 0
B

The choice is b because the graph on the right illustrates that the range, which comprises all possible y values, extends infinitely in both positive and negative directions.
Leona [4.1K]6 days ago
4 0

The domain refers to all potential input values, specifically represented by the x-axis on a graph. Conversely, the range includes all possible output values, depicted along the y-axis.


The graph clearly extends horizontally from (-∞,∞) on the x-axis, indicating that its domain is (-∞,∞).


Similarly, it can be seen that the graph stretches vertically from (-∞,∞) on the y-axis, denoting that the range is also (-∞,∞).


This indicates the function includes an infinite array of values. Therefore, there are no limitations on either the domain or the range for this function.

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10 times as many as blank hundreds or 60 hundreds is blank thousands
Svet_ta [4341]

The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

  • 10 times a given quantity of _____ hundreds results in 60 hundreds
  • 60 hundreds convert to _____ thousands

We will divide this into two segments:

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }... Equation-1

\boxed{ \ 60 \times 100) = M \times 1,000 \ }... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }

\boxed{ \ 1,000 \times N = 6,000 \ }

Both parts will be divided by 1,000, essentially being multiplied by \frac{1}{1,000}.

\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }

Thus, we conclude with \boxed{\boxed{ \ N = 6 \ }}

Next, we process Equation-2 to derive M's value.

\boxed{ \ 60 \times 100) = M \times 1,000 \ }

\boxed{ \ 6,000 = M \times 1,000 \ }

Rearranging this equation to place M on the left side appears as follows:

\boxed{ \ M \times 1,000 = 6,000 \ }

Again, both sides undergo division by 1,000, which translates to multiplication by \frac{1}{1,000}..

\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }

This results in \boxed{\boxed{ \ M = 6 \ }}

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }

\boxed{ \ 6 \times thousands = \ M \ thousands} \ }

\boxed{\boxed{ \ M = 6 \ }}

Additional resources

  1. A more detailed version of this topic
  2. 2 thousands 7 tens divided by 10 equals what?
  3. 100 is equivalent to 1/10 of which number?

Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

4 0
11 days ago
Read 2 more answers
Write the number 0.21212121.. as a fraction let x=
AnnZ [3900]
To work with the repeating decimals, note that since there are two digits repeating, you will be using a 1 followed by two zeros, which is 100. This factor will be important for subsequent calculations.

Let’s denote the repeating decimal as x.

Thus, you can write

x = 0.212121...

Now, if you multiply this equation by 100, you can write it on top of the previous equation.
This results in:

100x = 21.212121...
x = 0.212121...

Next, set up a subtraction by taking the second equation from the first:

100x = 21.212121...
x = 0.212121...
- ----------------------------
99x = 21

Solving for x involves dividing both sides by 3:

33x = 7

Then, divide both sides by 33:

x = 7/33

Thus, we conclude that the repeating decimal 0.212121... equates to the fraction 7/33.

Answer: the fraction is 7/33
7 0
8 days ago
AA3+2=AAA<br>CC6+6=CBB<br> ABC= ?
Zina [3917]
From AA3+2=AAA, it follows that 3+2 equals A, so A must be 5.
Given CC6+6=CBB, since 6+6 equals 12, the final digit has to be 2, making B=2. Additionally, adding 6 to 6 increases the tens digit by one, meaning B is one more than C, so C=1 (since 2-1=1). Therefore, ABC equals 521.
9 0
17 days ago
Suri's age is 4 less than 3 times her cousin's age. Suri is 17 years old. Which method can be used to find c, her cousin's age?
zzz [4035]

Answer:

7 years

Step-by-step explanation:

Suri is 17 years old.

Her cousin's age is c.

Suri's age is stated to be 4 less than 3 times her cousin’s age.

This means we take 3 times her cousin’s age and subtract 4.

17 = 3c - 4

We now need to solve for c, which represents her cousin's age.

Add 4 to each side:

17 + 4 = 3c - 4 + 4

17 + 4 = 3c

21 = 3c

Now divide both sides by 3:

21/3 = 3c/3

7 = c

Thus,

Her cousin is 7 years old.

4 0
3 days ago
The total amount of water a tank can hold is 14 and one-half gallons. Raul wants to find out how many 1 and one-fourth-gallon bu
lawyer [4039]

Answer:

The total capacity of the tank is 14 1/2 gallons or 29/2.

The size of bucket is 1 1/4 gallons, equal to 5/4.

The expression representing this situation can be

29/2 divided by 5/4.

Therefore, the number of buckets applied equals 29/2 multiplied by 4/5.

5 0
10 hours ago
Read 2 more answers
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