Imagine the world in 2030 and write a letter to your future self. Be sure to mention things that you think your future self woul

Answer:

Explanation:

When removing items from a dictionary, always specify the key in quotation marks.

For example: del country_capital['Prussia']

Failing to place it in quotes will cause the interpreter to view Prussia as a variable, resulting in an error saying that Prussia is not defined.

Code:

user_input=input("") #taking input from user

entries=user_input.split(',')    

country_capital=dict(pair.split(':') for pair in entries) #creating the dictionary from user input

del country_capital['Prussia'] #removing Prussia; failure to include quotes results in an error

print('Prussia deleted?', end=' ')

if 'Prussia' in country_capital: #verifying the presence of Prussia in the dictionary

print('No.')

else:

print('Yes.')

print ('Spain deleted?', end=' ')    

if 'Spain' in country_capital: #checking if Spain is present in the dictionary

print('No.')

else:

print('Yes.')

print ('Togo deleted?', end=' ') #verifying the existence of Togo in country_capital

if 'Togo' in country_capital:

print('No.')

else:

print('Yes.')

Explanation:

Answer:

a) Transforming each character into its binary equivalent:

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

Likewise

F4:

F stands for 15 and its binary is: 1111

4 in binary: 100

Consequently

F4:  1_111_0100

E5:

E corresponds to 14 and its binary form is: 1110

5 in binary: 101

Therefore

E5:  1_110_0101

76:

7 in binary: 111

6 in binary: 110

Hence

76:  0_111_0110

E5:

E has a binary representation of: 1110

5 in binary: 101

Consequently

E5:  1_110_0101

4A:

4 in binary: 100

A represents 10

A in binary form: 1010

Therefore

4A:  0_100_1010

EF:

E in binary is: 1110

F in binary is: 1111

Thus

EF: 1_110_1111

62:

6 in binary form: 110

2 in binary form: 10

Therefore

62:  0_110_0010

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

for 0_1110011: the decimal equivalent is: 115 which translates to s

for 1_1110100:  the decimal equivalent is: 116 which translates to t

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1110110: the decimal equivalent is:  118 which translates to v

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1001010: the decimal equivalent is:  74 which translates to j

for 1_1101111: the decimal equivalent is: 111 which translates to o

for 0_1100010:  the decimal equivalent is: 98 which translates to b

for 0_1110011: the decimal equivalent is:  115 which translates to s

Thus the decoded sequence is:  stevejobs

b) The parity being utilized is odd.

for 0_1110011:  There are 5 instances of 1s and the parity is 0 indicating it is odd.

for 1_1110100: There are 4 instances of 1s and the parity is 1 indicating it is odd.

Thus, we count the number of 1s and then verify if the parity is odd or even.

Likewise

for 1_1100101:  the parity is odd

for 0_1110110: the parity is odd

for 1_1100101:  the parity is odd

for 0_1001010: the parity is odd

for 1_1101111: the parity is odd

for 0_1100010: the parity is odd

for 0_1110011: the parity is odd

Therefore, the parity being used is odd.