Answer: La probabilidad que necesitamos es 0.16.
Step-by-step explanation:
Se nos proporciona que
La probabilidad de que el estudiante sea un senior = 0.22
La probabilidad de que el estudiante tenga una licencia de conducir = 0.30
La probabilidad de que el estudiante sea un senior o tenga una licencia de conducir = 0.36
Buscamos la probabilidad de que el estudiante sea un senior y tenga licencia de conducir.
Según la pregunta,

Por lo tanto, la probabilidad que necesitamos es 0.16.
The increase in production is found by calculating 180 - 150 = 30 tons. The percentage rise is computed by taking 30 divided by 150, which equals 0.2 or a 20% rise.
Answer:
The anticipated number of tests required to identify 680 acceptable circuits is 907.
Step-by-step explanation:
For any circuit, there are two potential results: it either passes the test or it fails. The likelihood of passing is independent between circuits. Therefore, we apply the binomial probability distribution to address this scenario.
Binomial probability distribution
This distribution calculates the chance of obtaining exactly x successes across n trials, where x has only two possible outcomes.
To find the expected number of trials to achieve r successes with a probability p, the formula is given by:

Circuits from a specific factory pass a certain quality evaluation with a probability of 0.75.
Thus, to determine the expected number of tests needed for 680 acceptable circuits, let’s denote this as E where r = 680.



The expected number of tests necessary to find 680 acceptable circuits is 907.