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Naily
6 days ago
15

How does the value of the digit 8 in 1.8 compare to the value of the digit 8 in 486?

Mathematics
1 answer:
Zina [9.1K]6 days ago
5 0

Answer:

refer to the process

Step-by-step explanation:

We see that

1.8=1+0.8

486=400+80+6

Thus,

The value of the digit 8 in 1.8 is 0.8

While the value of the digit 8 in 486 is 80

Now dividing these values

80/0.8=100

So

The value of the digit 8 in 486 is 100 times larger than that of the digit 8 in 1.8

or

The value of the digit 8 in 1.8 is 100 times smaller compared to the value of digit 8 in 486

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The shortest person in a class is 55 inches tall and tallest person in that class is 75 inches tall. Write an absolute value equ
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x = lowest height

<x+25 highest height

x=55

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Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
lawyer [9226]
Utilize the details to create inequalities that reflect each limitation or requirement.

2) Label the variables. 

c: count of color copies
b: count of black-and-white copies

3) Define each constraint:

i) <span>Printing a color copy requires 3 minutes while a black-and-white copy takes 1 minute.
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</span><span>3c + b
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</span><span>ii) He must print a minimum of 6 copies ⇒ c + b ≥ 6
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</span><span>iv) Moreover, he must finish the prints within 12 minutes at most ⇒</span>

3c + b ≤ 12
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4) Additional limits include c ≥ 0, and b ≥ 0 (meaning only non-negative counts are valid for each type of copy)

5) Here’s how to illustrate that:

i) For 3c + b ≤ 12: draw the line representing 3c + b = 12 and shade the area above and to the right of this line.

ii) For c + b ≥ 6: draw the line c + b = 6 and shade the area below and to the left of this line.

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6 0
16 hours ago
What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S
PIT_PIT [9101]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Detailed breakdown:

3k / (k + 1) × (k² - 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

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4 0
17 days ago
6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of
PIT_PIT [9101]

Response:

Charlie can purchase a maximum of 0.375 pounds of potato salad

Detailed explanation:

Refer to the figure provided for improved clarity on the issue

Let

a ----> the price of one tuna sandwich

b ----> the price of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

a=\$4.25

b=\$2.25

c=\$4.00/lb

he intends to buy a tuna sandwich, a bottle of apple juice, and x pounds of potato salad, and his spending limit is $8

The corresponding inequality for this scenario is

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Combine similar terms

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Decrease 6.50 from both sides

4.00x \leq 8-6.50

4.00x \leq 1.50

Divide both sides by 4

x \leq 1.50/4.00

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Charlie can acquire a maximum of 0.375 pounds of potato salad

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3 days ago
The cube shown has side length 0.7 metres.
Leona [9260]

Answer:

294cm

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6 × a² (side length)

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6 × 0.7 × 0.7 = 2.94m

Final result = 294cm.

8 0
1 month ago
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