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natta225
6 days ago
9

Two factories — Factory A and Factory B — design batteries to be used in mobile phones. Factory A produces 60% of all batteries,

and Factory B produces the other 40%. 2% of Factory A's batteries have defects, and 4% of Factory B's batteries have defects. What is the probability that a battery is both made by Factory A and defective? *
Mathematics
1 answer:
tester [3.9K]6 days ago
4 0

Answer:

The likelihood of a battery being produced by Factory A and being defective is 0.012, which corresponds to 1.2%.

Step-by-step explanation:

We have two manufacturers of batteries for mobile phones: Factory A and Factory B. Factory A is responsible for 60% of the total battery production, while Factory B accounts for the remaining 40%.

Out of the batteries made by Factory A, 2% are found to be defective, whereas 4% of those from Factory B are defective.

Let P(A) denote the probability that a battery comes from Factory A, therefore P(A) = 0.60.

The probability that a battery originates from Factory B can be denoted as P(B) = 0.40.

Furthermore, define D as the event indicating that a battery is defective.

Thus, the probability of a defect given that a battery is from Factory A is P(D/A) = 0.02.

For Factory B, the probability of a defect given it is from there is P(D/B) = 0.04.

The probability for a battery being made at Factory A and also being defective can be calculated as follows:

Probability that Factory A produces batteries \times Probability that a battery from Factory A is defective

                       =  P(A) \times P(D/A)

                       =  0.60 \times 0.02 = 0.012  or  1.2%

Conclusively, the probability that a battery is both from Factory A and defective is 1.2%.

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Distributions from owners refer to payments that business owners take out from profits the firm earns, commonly issued as dividends. An ADR, or American Depositary Receipt, is a type of stock bought and sold within the U.S. market that represents a specific number of shares in a foreign company. Therefore, the owner’s payments do not originate from the ADR shares.
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13 days ago
A man standing at a window 5 meters tall watches a falling ball pass by the window in 0.3 seconds. From how high above the top o
babunello [3666]

Answer:

The height is 11.76 meters.

Step-by-step explanation:

To solve this problem, the following equations are necessary:

The first one relates initial and final velocities, taking into account that gravity is 9.81 m/s² and the time is 0.3 seconds:

Vf = Vo + g * t = Vo + 9.81 * 0.3

Vf = Vo + 2.94 (1)

The second one also connects initial and final velocities, but this time with distance S, which we know to be 5 meters:

Vf² = Vo² + 2 * g * S

Vf² = Vo² + 2 * 9.81 * 5

Vf² = Vo² + 98.1 (2)

We now have two equations with two unknowns. By substituting (1) into (2):

(Vo + 2.943)² = Vo² + 98.1

Vo² + 5.886 * Vo + 8.66 = Vo² + 98.1

Canceling Vo² and rearranging gives us:

Vo = 89.44 / 5.886

Vo = 15.195 m/s

Now using the formula:

Vo² = 2 * g * h

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4 0
5 days ago
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
zzz [4035]

Answer:

A.) 1508; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

The general equation for an exponential model is:

A = A0e^rt

A0 represents the initial population

A indicates the final population

r is the growth rate; t denotes time

1)

Considering the years 1750 and 1800

Time interval, t = 1800 - 1750 = 50 years

Starting population = 790

End population = 980

To find the growth rate:

980 = 790e^50r

980/790 = e^50r

Applying the natural logarithm to both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this growth rate, let's forecast the population for 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788; approximately 1508 million people

In 1950:

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467; around 1870 million people

2.)

Exponential model from 1800 to 1850

Initial population in 1800 = 980

Final population in 1850 = 1260

t = 1850 - 1800 = 50

Utilizing the exponential equation, we find the growth rate:

1260 = 980e^50r

1260/980 = e^50r

Taking the natural logarithm of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Utilizing this model, the anticipated population in 1950:

In 1950:

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571; approximately 2083 million people

3.)

For 1900: 1650,

For 1950: 2560

t = 1900 - 1950 = 50

Utilizing the exponential formula, we derive the growth rate:

2560 = 1650e^50r

2560/1650 = e^50r

Logarithm both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using this model, the projected population for 2000:

In 2000:

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787; approximately 3972 million people

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