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xxTIMURxx
3 months ago
9

If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK

Mathematics
1 answer:
lawyer [12.5K]3 months ago
4 0

Response:

The measure of mHLK is "(204)°".

Step-by-step breakdown:

Given values include:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

What is mHLK?

Now,

Utilizing the chord-chord angle formula, we find

mHMK=\frac{1}{2}(mJL+mHLK)

Inserting the known values into the equation gives us

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

By carrying out cross-multiplication, we arrive at

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

By subtracting "18x" from both sides, we obtain

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

Upon adding "2" to both sides, we end up with

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

By substituting the value of "x" into mHLK = (15x-36)°, we calculate

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

Thus, mHLK = (204)°

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