The math equation to solve is 36 + 34 + 25, and the sum is 95.
The diagonal that crosses the interior of the cube is the longest segment. The hypotenuse corresponds to the longest side in a right triangle. In this case, the cube's diagonal serves as the hypotenuse of a right triangle, with the legs being the diagonal of one of its faces and one of its edges. The edges are the shortest sections and function as the legs of a right triangle where the face's diagonal acts as the hypotenuse.
When there is one table (t=1), you can place 6 chairs (c=6) around it: 2 along the length of each side and 1 at each end.
With t=2, where the tables are positioned end to end (joined at the width), c=10, that means 4 chairs along each side of the joined tables and 1 chair at each end. Each additional table increases the number of chairs by 4, thus we can express this as c=4t+2, with the constant 2 representing the individual chair at each end. If the tables are spread apart, then c=6t.
A matching complex for 2+3i is required. The conjugate is 2-3i, leading to the factors (x-2-3i)(x-2+3i)=(x²-4x+4+9)=x²-4x+13. The resulting polynomial is (x-4)(x+8)(x²-4x+13)=(x²+4x-32)(x²-4x+13)=x⁴-4x³+13x²+4x³-16x²+52x-32x²+128x-416, resulting in the 4th degree polynomial: x⁴-35x²+180x-416.
