Answer:
a. 0
b. Yes
c. The claim made by the manufacturers is not credible
d. 0.3446
e. A mean lifetime of 39.8 hours is not considered unusually short.
f. The manufacturers claim is credible
Step-by-step explanation:
Please see attachment
Let’s clarify this: the basketball moves faster, indicating the tennis ball won’t be able to catch up. Therefore, we utilize the formula:
Vr=Vb-Vt
<span>=0.5-0.25=0.25
</span>Thus, the relative speed is <span>0.25m/s.
I hope this is helpful.</span>
Answer:
0.93 minute
Step-by-step explanation:
During the first week:
Kim ran = 1 mile
Duration for this distance = 1 minute
In the second week:
The distance covered by Kim = 1 mile
The time taken by Kim = 7% less compared to the first week
= 1 min - 0.07 min = 0.93 minute
<pSo, she completed 1 mile in 0.93 minute this week.
Response:
$144,843.5
Detailed explanation:
In this scenario, we will utilize the compound interest formula
A= P(1+r)^t
A = final amount
P = initial principal
r = interest rate
t = number of periods
Given parameters
P= $27,000
R= 7.25%= 7.25/100= 0.0725
T= 24
A=27000(1+0.0725)^24
A= 27000(1.0725)^24
A= 27000*5.364
A= $144,843.5
By the end of 24 years, her account balance will reach $144,843.5
Set A's standard deviation exceeds that of Set B. To explain, standard deviation reflects variation within data sets. Generally, a dataset with a narrower range will exhibit a smaller standard deviation. For Set A, the range is 25-1 = 24, while for Set B, it's 18-8 = 10. Given that Set A's range is bigger, we would anticipate its standard deviation to also be larger. Standard deviation is calculated as the square root of the average of the squared deviations from the mean. In Set A, the deviations are ±12, ±11, ±10, whereas Set B's deviations are ±5, ±3, ±1. We can reasonably conclude that the value for Set A will be greater without computing the RMS difference. Thus, Set A's standard deviation is larger compared to Set B.
