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ale4655
1 month ago
15

Sari estimated the quotient of 120.78 ÷ 9.9 to be 12. She said that her estimate is slightly greater than the actual answer. Is

she correct? Is her estimate reasonable? Explain.
Mathematics
2 answers:
AnnZ [12.3K]1 month ago
7 1

Response:

sample response: Sari made a reasonable guess for the task. However, it was incorrect for her to claim that her estimate was just above the actual figure. The approximated dividend, 120, is marginally under 120.76, while the rounded divisor, 10, is a bit more than 9.9, leading to an estimate that would be lower than the true quotient.

Detailed explanation:

I completed the practice test on edge:>

PIT_PIT [12.4K]1 month ago
5 0

Response:

Indeed, her projection exceeds the true answer. 120.78 divided by 9.9 equals 12.2. Given that 12.2 (the actual result) is more than her estimate of 12, she is correct.

Detailed explanation:

Refer to Response.

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Answer:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

Step-by-step explanation:

Notation

\bar X is the sample mean

\mu indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In this instance, the 9% confidence interval corresponds to:

8.8104 \leq \mu \leq 11.1248

We can determine the mean using the following:

\bar X = \frac{8.8104 +11.1248}{2}= 9.9676

Additionally, the margin of error can be calculated as:

ME= \frac{11.1248- 8.8104}{2}= 1.1572

The margin of error for this situation is expressed as:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE

Next, we find the standard error:

SE = \frac{ME}{t_{\alpha/2}}

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

SE = \frac{1.1572}{1.96}= 0.5904

For the 98% confidence interval, the significance corresponds to \alpha=1-0.98= 0.02 and \alpha/2 = 0.01 with a critical value of 2.326, yielding a confidence interval of:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

8 0
1 month ago
The half-life of carbon-14, 14C, is approximately 5,730 years. A bone fragment is estimated to have originally contained 6 milli
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A statistics teacher was interested in the relationship between the number of days students waited to start a project and the sc
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Answer:

A: With each additional procrastination day, the expected grade drops by 3.64 points.

Step-by-step explanation:

The slope of a Regression Line

A linear equation can be expressed in slope-intercept form:

y = mx + b

Here, m represents the slope and b indicates the y-intercept.

The slope reveals the rate and direction of change in the graph as x varies.

<pif m="" is="" positive="" increases="" in="" x="" result="" y.="">

If m is negative, increases in x lead to decreases in y.

<pthe regression="" equation="" is:="">

ŷ = –3.64x + 96.5

Where:

x = number of procrastination days

ŷ = anticipated grade

<pthus the="" slope="" is="" m="-3.64." this="" indicates:="">

A: With each additional procrastination day, the expected grade drops by 3.64 points.

</pthus></pthe></pif>
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