Response:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) signifies the likelihood that a student with a visa card also possesses a MasterCard.
p(A/B) indicates the probability that a student with a MasterCard also has a visa card.
e. 0.35
f. 0.31
Detailed explanation:
a. p(AUBUC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.11 - 0.1 + 0.07 = 0.76
b. P(AnBnC') = P(AnB) - P(AnBnC)
= 0.3 - 0.07 = 0.23
c. P(B/A) = P(AnB)/P(A)
= 0.3/0.6 = 0.5
e. P((AnB)/C) = P((AnB)nC)/P(C)
= P(AnBnC)/P(C)
= 0.07/0.2 = 0.35
f. P((AUB)/C) = P((AUB)nC)/P(C)
= (P(AnC) U P(BnC))/P(C)
= (0.11 + 0.1)/0.2
= 0.21/0.2 = 0.31
