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3 months ago

In triangle LTM, segment XY is the perpendicular bisector of side TM.

Mathematics

1 answer:

Leona [12.6K]3 months ago

5 0

This is definitely option c, I'm sure of it lol.

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Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr

Inessa [12570]

Answer:

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

Step-by-step explanation:

Given the quadratic equation:

$x^2 = -11x + 4$

To solve it, we follow these steps:

1. Rearrange the terms to one side of the equation:

$x^2+11x- 4=0$

2. Utilize the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ .

In this case, we can identify that:

$a=1\\b=11\\c=-4$

Then, substituting these values into the Quadratic formula gives us the following solutions:

$x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}$

$x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}$

3 0

2 months ago

Read 2 more answers

WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the

Inessa [12570]

Answer:

a) $P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)$

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

$P(z>1.43)=1-P(z$

b) $P(X$

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

$P(z$

c) $P($

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

$P(-1.43$

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

$X \sim N(15,3.5)$

Where $\mu=15$ and $\sigma=3.5$

We seek the probability:

$P(X>20)$

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

$z=\frac{x-\mu}{\sigma}$

By applying this formula, we can find the probability:

$P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)$

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

$P(z>1.43)=1-P(z$

Part b

$P(X$

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

$P(z$

Part c

$P($

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

$P(-1.43$

5 0

3 months ago

The Spirit Team will be selling popcorn as a fundraiser at the next basketball game to earn funds to go to Orlando for a competi

zzz [12365]

Response:1 and 2

Step-by-step Explanation:

Provided data

Volume required $V=220\ in.^3$