Segment GI is congruent to Segment JL and Segment GH is congruent to Segment KL. I have to prove Segment HI is congruent to Segm

I think the answer is A
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Answer:

Step-by-step explanation:

The given formula doesn't appear to match any of the answer choices.

  W = (P/2) - L

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:

The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.

The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.

Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.

b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.

The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.

Answer:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

Detailed Breakdown:

An illustrative depiction of the question has been provided in an image format for clarity.

From the information given, it is noted that her store order arrived on 12/3/2016 at 4am, confirming that both the prep date and time are 12/3/2016 and 4am respectively. The product has a printed expiration date of 1/17/2017, logically indicating that its expiration time is also 4am, in line with the prep time; adding 24 hours leads us back to the same time on the expiration date. Furthermore, we were informed that she utilized the product on 12/7/2016, which marks the initial use date. Based on this information, we can summarize as follows:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

Answer: All real numbers except for x ≠ 7 and those x for which f(x)≠-3

Step-by-step explanation:

The domain of function f is defined as R - {7}

In other words, if x belongs to the domain of f,

then, x cannot equal 7

(gof)(x) = g(f(x))

Considering that g has a domain of R - {-3}

Therefore, if f(x) fits within the domain of g,

it follows that f(x)≠ -3

Consequently, the fourth option is the right choice.