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1 month ago

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After soccer practice coach Miller goes to the roof of the school to retrieve the event soccer balls the height of the school is

3.5 m a soccer ball which leaves the roof with only a horizontal velocity of 15 m/s in the ignoring air resistance how far is the ball above the ground at 0.32 seconds

1 answer:

Yuliya22 [3.3K]1 month ago

4 0

Answer:

50.2 cm

Explanation:

We have the following data:

Height, h=3.5 m

Initial horizontal velocity, $u_x=15 m/s$

Time, t=0.32 s

We need to determine how far the ball is from the ground after 0.32 s.

Initial vertical velocity, $u_y=0$

$s=u_yt+\frac{1}{2}gt^2$

Where $g=9.8 m/s^$

$s=0+\frac{1}{2}(9.8)(0.32)^2$

$s=0.502 m$

$s=0.502\times 100=50.2 cm$

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