Response:
Reasoning:
We will utilize a Gaussian surface that resembles the curved wall of a cylinder, with a radius of 3mm and a length of 1 unit directed parallel to the wire axis.
The charge within this cylinder amounts to 250 x 10⁻⁹ C.
Let E denote the electric field at the curved surface, perpendicular to it.
The total electric flux leaving the curved surface
is calculated as 2π r x 1 x E
or 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's law, the total flux is given by the charge within divided by ε (the charge inside the cylinder being 250 x 10⁻⁹C)
equals 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² (where ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹²)
resulting in 11.3 x 10³ weber.
Thus,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
=.599 x 10⁶ N /C.
Answer:
Competitive forces model
Explanation:
The Competitive forces model is a crucial instrument in strategic analysis aiming to assess an organization’s competitiveness. Commonly referred to as the "Five Force Model of Porter", this framework includes five key factors: the intensity of rivalry among existing competitors, the negotiating power of buyers, the threat posed by potential new entrants, the bargaining strength of suppliers, and the risk of substitute products or services.
These elements significantly influence an organization's competitive strategy and its likelihood of success.
Flow rate calculations yield 220 cans, each with a volume of 0.355 l, leading to 78.1 l/min or 1.3 l/s or 0.0013 m³/s.
At Point 2:
A2 = 8 cm² = 0.0008 m²
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa
At Point 1:
A1 = 2 cm² = 0.0002 m²
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 =?
Height = 1.35 m
Using Bernoulli’s principle;
P2 + 1/2 * V2² / density = P1 + 1/2 * V1² / density + density * gravitational acceleration * height
=> 152000 + 0.5 * (1.625)² * 1000 = P1 + 0.5 * (6.5)² * 1000 + (1000 * 9.81 * 1.35)
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31 - 34368.5 = 118951.81 Pa = 118.95 kPa
The greatest mass that can hang without submerging is 2.93 kg. The provided details are as follows: sphere diameter = 20 cm, hence the radius r = 10 cm = 0.10 m. The density of the Styrofoam sphere is 300 kg/m³. The sphere's volume calculates to 4.18 * 10⁻³ m³. Mass M = Density * Volume results in (300)(4.18 * 10⁻³ m³) = 1.25 kg. The displaced water mass is computed as volume * water density, yielding 4.18 * 10⁻³ m³ * 1000 = 4.18 kg. The additional mass the sphere can hold is the difference between the two mass calculations: 4.18 kg - 1.25 kg = 2.93 kg.
