<span>First, apply Newton's second law of motion: F = ma.
Force equals mass times acceleration.
This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time,
we have force = (mass * velocity) / time,
leading us to conclude that (mass * velocity) / time will equal momentum / time.
Hence, we derive the equation mass * velocity = momentum.
Momentum = mass * velocity.
For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s,
Momentum = 6300 * 0.11,
resulting in P = 693 kg (m/s).
For the dolphin, having a mass of 50 kg and moving at 10.4 m/s,
Momentum = 50 * 10.4,
yielding P = 520 kg (m/s).
Thus, the elephant has a greater momentum (P) due to its larger size.</span>
Answer:
b = 0.6487 kg / s
Explanation:
In the context of oscillatory motion, friction is related to velocity,
fr = - b v
where b represents the friction coefficient.
Upon solving the equation, the angular velocity is represented as
w² = k / m - (b / 2m)²
In this case, we're given an angular frequency w = 1Hz, the mass m = 0.1 kg, and the spring constant k = 5 N / m. This allows us to derive the friction coefficient.
Let’s denote
w₀² = k / m
w² = w₀² - b² / 4m²
b² = (w₀² -w²) 4 m²
Now, let's calculate the angular frequencies.
w₀² = 5 / 0.1
w₀² = 50
w = 2π f
w = 2π 1
w = 6.2832 rad / s
Substituting values yields
b² = (50 - 6.2832²) 4 0.1²
b = √ 0.42086
b = 0.6487 kg / s
Answer:
La magnitud del EMF es 0.00055 volts
Explanation:
El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

Necesitamos expresar el flujo magnético dada la geometría del problema;
donde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:

It shows a situation where a proton moves perpendicular to a magnetic field of 0.025 tesla. The force acting on the proton has a magnitude of 1.8 × 10⁻¹⁴ newtons, and we need to determine the speed of the proton given q = 1.6 × 10⁻¹⁹ coulombs.