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romanna
3 months ago
6

You need two bottles of fertilizer to treat the flower garden shown. How many bottles do you need to treat a similar garden with

a perimeter of 105 feet? A flower garden in the form of trapezoid is shown. The length of longer base is labeled 18 feet, shorter base is 15 feet, height is 4 feet, and one leg is 5 feet.
Mathematics
1 answer:
Inessa [12.5K]3 months ago
3 0

Response:

26.25 bottles

Detailed explanation:

The trapezoidal flower garden is depicted. The longer base measures 18 feet, the shorter base is 15 feet, the height is 4 feet, and one side measures 5 feet.

The formula for the perimeter of a trapezoid is: Side a + side b + length a + length b

For the trapezoid in question, to calculate the perimeter, first, we identify the missing length

Length a

Height is given as 4 feet

Longer base length = 18 feet

Shorter base length = 15 feet

The difference will determine the base of the right triangle

= 18 - 15 = 3 feet

Using the Pythagorean theorem allows us to calculate side a = c

a² + b² = c²

3² + 4² = c²

9 + 16 = c²

c = √25

c = 5 feet

Therefore, side a = 5 feet

The perimeter of the trapezoid is calculated as:

18 feet + 15 feet + 5 feet + 5 feet

= 38 feet.

The question states,

It's necessary to use 2 bottles of fertilizer for the flower garden shown. Determine how many bottles are needed for a similar garden with a perimeter of 105 feet

Thus:

38 feet = 2 bottles

105 feet = x bottles

Cross multiplying yields

= 38 × x = 105 × 2

= 38x = 210

x = 210 / 38

x = 26.25 bottles

To treat the garden with a perimeter of 105 feet, 26.25 bottles of fertilizer are required.

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zzz [12365]

Response: (15.263,\ 17.537)

Step-by-step analysis:

Based on the information provided, we note

Sample size: n= 50

\overline{x}=16.40

s=4.00

Given that the population standard deviation is not known, a t-test is employed.

Critical value for the 95 percent confidence interval:

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval: \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval: (15.263,\ 17.537)

8 0
2 months ago
In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
Inessa [12570]
In response to the earlier inquiry, the diagram depicts horizontal lines along with a vertical segment; FB measures 3. If C is defined as 3, then the coordinates for point D would be (-6,-4). I trust this response has clarified your question.
8 0
2 months ago
Read 2 more answers
The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin
PIT_PIT [12445]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

The details provided in the question are:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

The weights are distributed in a bell-shaped normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We need to determine the value of x for which the probability is 0.03.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03  

=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97  

Using the standard normal z table, we find that,

\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12  

Thus, the value of 8.17 g separates the upper 3% of the weights.

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03  

From the standard normal z table, we derive,

\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90  

Consequently, 7.90 separates the lower 3% of the weights.

<ptherefore the="" accurate="" answer="" is="">

Option D) 7.90 g and 8.12 g

</ptherefore>
7 0
2 months ago
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