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mariarad
1 month ago
12

The velocity of a ball is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average acceler

ation of the ball during its upward flight?
Mathematics
2 answers:
PIT_PIT [12.4K]1 month ago
7 0
Average acceleration can be calculated as (v - v₀) / Δt.
Here, v = 0 m/s, v₀ = 20 m/s, and Δt = 3.5 s.
Thus, a (average) = (0 m/s - 20 m/s) / 3.5 s = -20 m/s / 3.5 s =
= -5.7142857 m/s² ≈ - 5.71 m/s²
PIT_PIT [12.4K]1 month ago
7 0

Answer:

Average acceleration = 5.714 meter per second²

Step-by-step explanation:

A ball is thrown upwards with an initial speed of 20 meters per second.

After 3.5 seconds, its speed drops to zero, indicating it has reached the peak height.

We now need to find the average acceleration during the ascent.

Thus, \text{Acceleration}=\frac{\text{Change in velocity}}{\text{Duration of motion}}

Acceleration = \frac{20-0}{3.5}

                       = 5.714 meter per second²

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Answer: The ratio needed will be 20:6:15.

Step-by-step explanation:

Given that

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We should simplify the quantities of water, sucrose, and saline solution to their lowest terms.

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As per the information provided,

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