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mariarad
6 days ago
12

The velocity of a ball is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average acceler

ation of the ball during its upward flight?
Mathematics
2 answers:
PIT_PIT [3.9K]6 days ago
7 0
Average acceleration can be calculated as (v - v₀) / Δt.
Here, v = 0 m/s, v₀ = 20 m/s, and Δt = 3.5 s.
Thus, a (average) = (0 m/s - 20 m/s) / 3.5 s = -20 m/s / 3.5 s =
= -5.7142857 m/s² ≈ - 5.71 m/s²
PIT_PIT [3.9K]6 days ago
7 0

Answer:

Average acceleration = 5.714 meter per second²

Step-by-step explanation:

A ball is thrown upwards with an initial speed of 20 meters per second.

After 3.5 seconds, its speed drops to zero, indicating it has reached the peak height.

We now need to find the average acceleration during the ascent.

Thus, \text{Acceleration}=\frac{\text{Change in velocity}}{\text{Duration of motion}}

Acceleration = \frac{20-0}{3.5}

                       = 5.714 meter per second²

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In right triangle qrs, angle r is a right angle. The altitude rt is drawn to hypotenuse qs. If qr is 20 and qs is 25 then find t
lawyer [4039]

Answer:

qt's length = 16

Step-by-step explanation:

The problem states that qrs is a right triangle,

where qr = 20

          sr =?

          qs = 25

          qt =?

1)

Calculate sr

hypotenuse² = base² + height²

sq² = sr² + rq²

25² - 20² = sr²

sr = √(25² - 20²)

sr = 15

2)

When altitude rt is dropped to hypotenuse qs, it creates

two right triangles: rtq and rts.

Δrtq

height = rt

base= tq = 25 - x

hypotenuse = qt = 20

Δrts

height = rt

base= ts = x

hypotenuse = sr = 15

Both triangles share the same height, which is rt

Using the Pythagorean theorem:

      Δ rtq                                           Δ rts

hypotenuse² - base² = height²

20² - (25 - x)² = 15² - x²

400 - (625 + x² - 50x) = 225 - x²

400 - 625 - x² + 50x = 225 - x²

-225 - x² + 50x - 225 + x² = 0

-450 + 50 x = 0

50x = 450

x = 450/50

x = 9

Base of Δ rtq = tq = 25 - x

                         tq = 25 - 9

                         tq = 16  

5 0
9 days ago
Read 2 more answers
"Our customer retention rate has decreased 10% from last quarter's goal of 250 consumers retained. We need to increase our curre
Zina [3917]

1. Calculate 10% of 250 (250 × 0.10 = 25)
2. Subtract that from 250 (250 - 25 = 225)
3. Then find 16% of 225 (225 × 0.16 = 36)
4. Add 225 and 36 to get 261
5. Therefore, the target number of consumers retained is 261
6 0
18 days ago
What is the main reason Dylan uses the word uses the word “lonesome” to describe Hattie Carroll’s death?
lawyer [4039]

The correct answer is B. No one stood up for her

The song primarily addresses the racism prevalent in our nation. Dylan highlights that the murderer was not penalized initially; he was released on the night of the homicide due to his wealth, and during the trial, he received only a six-month term instead of a meaningful punishment. Hattie Carroll was largely overlooked in this scenario.

8 0
12 days ago
Energy drink consumption has continued to gain in popularity since the 1997 debut of Red Bull, the current leader in the energy
tester [3938]

Answer:

1. 3.767

2. 0.145

Step-by-step explanation:

Define X as the exam scores and Y as the number of drinks.

X     Y   X-Xbar    Y-Ybar   (X-Xbar)(Y-Ybar)    (X-Xbar)²       (Y-Ybar)²    

75    5    -2.3          2.3          -5.29                      5.29              5.29

92    3     14.7         0.3           4.41                       216.09           0.09

84    2     6.7         -0.7           -4.69                     44.89             0.49

64    4     -13.3        1.3           -17.29                     176.89           1.69

64    2     -13.3       -0.7           9.31                       176.89           0.49

86    7     8.7           4.3           37.41                     75.69            18.49

81     3     3.7           0.3           1.11                         13.69             0.09

61     0    -16.3        -2.7           44.01                     265.69          7.29

73    1      -4.3         -1.7            7.31                        18.49             2.89

93    0    15.7         -2.7           -42.39                    246.49          7.29

sumx=773, sumy=27, sum(x-xbar)(y-ybar)= 33.9, sum(X-Xbar)²= 1240.1,sum(Y-Ybar)²= 44.1

Xbar=sumx/n=773/10=77.3

Ybar=sumy/n=27/10=2.7

1.

Cov(x,y)=sxy=\frac{Sum(X-Xbar)(Y-Ybar)}{n-1}

Cov(x,y)=33.9/9

Cov(x,y)=3.76667

Thus, the sample covariance of exam scores and energy drink consumption is 3.767

2.

Cor(x,y)=r=\frac{Sum(X-Xbar)(Y-Ybar)}{\sqrt{Sum(X-Xbar)^2sum(Y-Ybar)^2} }

Cor(x,y)=r=\frac{33.9}{\sqrt{(1240.1)(44.1)} }

Cor(x,y)=r=33.9/233.85553

Cor(x,y)=r=0.14496

The sample correlation coefficient for the relationship between exam scores and energy drink consumption is 0.145.

7 0
3 days ago
Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche
tester [3938]

Response:

The height of the water when it reaches 4 inches is \frac{3}{8\times \pi} inch/s.

Detailed Explanation:

Flow rate of water from the cone = R=\frac{3}{2} inch^3/s

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}

r = h/2

Volume of the cone = V=\frac{1}{3}\pi r^2h

V=\frac{1}{3}\pi r^2h

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}

\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}

\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}

\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}

h = 4 inches

\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}

\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2

\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s

The height of the water when it is 4 inches deep is \frac{3}{8\times \pi} inch/s.

6 0
11 days ago
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