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konstantin123
2 months ago
10

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

?10. 1m squared floor tiles costs ?3. Work out the total costs of tiles and paints
Mathematics
1 answer:
Leona [12.6K]2 months ago
5 0

Answer:

The combined expense for both tiles and paint amounts to $924.

Step-by-step explanation:

We know the community hall has a cuboid shape, measuring 40 meters in length, 15 meters in height, and 3 meters in width.

Paint coverage is needed for the four walls plus the ceiling.

Calculating the total area of walls and ceiling:

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

The total surface area requiring paint is 1,410 square meters.

Given: 10 liters of paint cost $10 and cover 25 square meters.

\text{ The total painting cost}=10*(\frac{1410}{25})

\text{ The total painting cost}=10*56.4=564

Therefore, the painting expense totals $564.

Floor tiling is required for the hall’s base. Calculating the floor area:

\text{Area of floor} = 40*3\text{ square meters}

\text{Area of floor} =120\text{ square meters}

Given: Floor tiles cost $3 per square meter.

\text{Total cost for tiles} = 3*120 = 360

The total tile cost comes to $360.

Finally, summing the cost of tiles and paint:

\text{Combined total cost}= 564+360 = 924

Thus, the overall cost for tiles and paint combined is $924.

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15 points!!!
PIT_PIT [12445]
8+292=300

8 out of 300 were defective.

\frac{8}{300}=\frac{x}{3000} \\ \\ 8*3000=300*x \\ \\ 24000=300x \\ \\ 80=x

That corresponds to 80 pairs being defective
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22 days ago
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Decimal 0.003 is 1/10 of
zzz [12365]
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Hence, the result is 0.03.

<span>I hope that was helpful!!!</span>
6 0
1 month ago
What is the product? (5r − 4)(r2 − 6r + 4)
Zina [12379]
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5 0
25 days ago
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If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components a
Svet_ta [12734]
The question is missing some information. It should be phrased as follows:

<span><span>A container has 50 electronic components, with 10 identified as defective. If 6 components are randomly selected from the container, what is the probability that at least 4 of them are not defective? Additionally, if 8 components are drawn at random from the container, what is the probability that exactly 3 are defective?

</span>Answers
<span>Part 1.  0.02
Part 2. </span></span>0.0375<span><span>

</span>Explanation
Probability denotes the likelihood of an event occurring. It is computed as:
probability = (Number of favorable outcomes)/(Number of total outcomes)

Part 1
When 6 components are chosen, if 4 are confirmed functioning, then 2 must be defective.
P(at least 4 functional) = 4/40</span>× 2/10
                                            = 1/10 × 1/5
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Part 2
Choosing 8 components, if 3 are defective, then 5 are functioning.
P(3 defective) = 3/40 × 5/10
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