One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, an

Answers:

The vertical asymptote is located at x = 0

The horizontal asymptote is identified as y = 0

The domain encompasses all real nonzero values

The range includes all nonzero real values

EXPLANATIONS

Given the function f(x) = c/x

c represents a non-zero real number

To find the vertical asymptote, we equate the denominator to 0

f(x)=c/x

The denominator is x

Setting x = 0

To establish the horizontal asymptote, we must compare the polynomial degrees in the numerator and denominator.

The numerator contains a polynomial of degree zero

While the denominator has a polynomial of degree one.

<span> Since the numerator's polynomial degree is less than that of the denominator, the horizontal asymptote is at y=0.</span>

Because the vertical asymptote is x = 0, the domain consists of all real numbers except x = 0

With the horizontal asymptote being y = 0, the range is all real numbers excluding y = 0

Answer:

Step-by-step explanation:

Let m denote the number of minutes required to download the entire game.

The computer downloads at a speed of 0.01 GB per minute, and since half a gigabyte has already been downloaded, we can express this as 0.01*m + 0.5 equaling 2.2, as the game's total size is 2.2 GB.

We will determine the minimum number of minutes necessary to completely download the game.

Thus, represents our sought inequality.

5 km. To determine the distance, we apply the speed formula that correlates distance with time: v = d / t. Thus, when rearranging for distance, we get: d = v * t. The speed is noted as 6 km/h, but we need to find the time taken - given he departs at 9:15 and returns at 10:05, the total time is 50 minutes. Converting this duration into hours gives us 50 min * 1 h / 60 min = 0.833 h. Hence, the duration for the journey to school is established as 0.833 hours. Substituting into our equation provides: d = 6 * 0.8333, yielding a distance of 5 km between the school and home.

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

Answer: 5 Cans

Step-by-step explanation: