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ollegr
3 months ago
6

One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, an

d let B be the event that the selected student drives to school. If P(A∩B)=0.08 and P(B|A)=0.25, what is the probability that the selected student will be a student athlete?
Mathematics
2 answers:
Inessa [12.5K]3 months ago
8 0

Answer:

0.32

Step-by-step explanation:

P(B|A) = P(A∩B) / P(A)

0.25 = 0.08 / P(A)

P(A) = 0.32

PIT_PIT [12.4K]3 months ago
4 0

Answer:

The likelihood that the randomly chosen student is a student athlete equals 0.32.

Step-by-step explanation:

Provided: A lone student will be selected randomly from a high school. Designate A as the event where the selected individual is a student athlete, and B as the event where the selected student drives to school.

Given values are P(A∩B)=0.08 and P(B|A)=0.25.

Need to determine: The probability of the selected student being a student athlete?

Solution:

A random selection will be made from high school students, and we inquire whether this student will qualify as a student athlete i.e. P(A)

Utilizing conditional probability,

P(B|A) =\frac{P(A\cap B)}{P(A)}

0.25= \frac{0.08}{P(A)}

P(A)= \frac{0.08}{0.25}

P(A)=0.32

Consequently, the likelihood that the selected student is an athlete equals 0.32.

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