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3 months ago

A sandbox is 2.5 m wide and 3.4 m long.

Mathematics

1 answer:

zzz [12.3K]3 months ago

5 0

Answer:

2.55 cubic meters of sand

Step-by-step explanation:

The inquiry focuses on how much sand is needed to completely fill the sandbox. As it is a three-dimensional shape, the concept of 'Volume' is applicable. Volume is determined through the formula L × W × H. By substituting the relevant variables into this equation, you arrive at the final solution. I hope this offers clarity!

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Jessica has 48 coins, some of them are nickels and some are dimes. How many of each does she have if she has $3.25 total?

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what is the method to create an equation

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3 months ago

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Claude spends $315 to rent a car. The car he rents costs $45 per day. He has a coupon for 2 free days. Complete the equation bel

AnnZ [12381]

He rents the car for d days, but receives two days at no cost, meaning he only needs to pay for d - 2 days.

Each day's rental costs $45, so for d - 2 days, the cost is 45(d - 2). The total expenditure amounts to $315, leading to the equation

45(d - 2) = 315

Now, let's solve for d, the number of days rented.

45(d - 2) = 315

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2 months ago

the volume of a sphere whose diameter is 18 centimeters is 246 324 648 972 π cubic centimeters. if its diameter were reduced by

Inessa [12570]

The sphere's radius is calculated as 18 divided by 2, giving 9 cm.

Using the formula for the volume of a sphere, we find it to be 4/3 πr^3, resulting in 4/3 x π x (9)^3 which equals 972 π cubic centimeters.

If we halve the diameter, the new volume can be calculated as: 4/3 x π x (9/2)^3 equals 4/3 x π x (9)^3 x (1/2)^3, simplifying down to 1/8 of 972.

Thus, the new volume will only be 1/8 of the original volume.

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3 months ago

A child who is trick-or-treating chooses a lollipop at random from a bowl of lollipops with mean weight 1.5 oz and standard devi

lawyer [12517]

Answer:

The anticipated total weight of the child's lollipop and two chocolate bars is 5.5 oz.

Step-by-step explanation:

Normal probability distribution

When dealing with a normal distribution, we apply the z-score formula.

In a dataset featuring a mean of $\mu$ and a standard deviation of $\sigma$ , the z-score for a value X is calculated as:

$Z = \frac{X - \mu}{\sigma}$

The Z-score indicates the number of standard deviations a measurement is from the mean. After computing the Z-score, we utilize the z-score table to find the corresponding p-value for this score. This p-value represents the probability that the measured value is less than X, essentially the percentile of X. By subtracting the p-value from 1, we determine the likelihood that the measured value exceeds X.

Adding normal variables:

The overall mean is the sum of individual means.

We calculate the expected combined weight of the child's lollipop and the two chocolate bars.

The child's lollipop averages 1.5 oz

Two chocolate bars average 2 oz each

Combining one lollipop and two chocolate bars gives

The total average is 1.5 + 2*2 = 5.5 oz

Hence, the expected combined weight of the child's lollipop and the two chocolate bars is 5.5 oz.

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3 months ago