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eimsori
2 months ago
15

Jessica has 48 coins, some of them are nickels and some are dimes. How many of each does she have if she has $3.25 total?

Mathematics
2 answers:
Inessa [12.5K]2 months ago
8 0

Answer:

unsure

Detailed explanation:

Svet_ta [12.7K]2 months ago
6 0

what is the method to create an equation

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The vertices of quadrilateral E F G H are E (-7,3) , F (-4,6) , G (5, -3) , and H (2,-6). What kind of quadrilateral is E F G H?
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The curvature of the Tacoma Narrows Bridge in
tester [12383]

Response:

The width of the arch measures 105 meters

Detailed explanation:

The function that describes the width of the arch is

f(x) = -0.016(x - 52.5)² + 45

where x denotes the horizontal distance from the left end of the arch or the width at its base

f(x) indicates the vertical height of the arch

According to the given quadratic equation, the vertex coordinates of the parabola are (52.5, 45).

The vertex coordinates indicate that

the arch's height is 45 meters

and half the horizontal span from the left end is 52.5 meters

Therefore, the bridge's total width is calculated as 2 times the half span from the left side, which is 2 × 52.5

resulting in 105 meters

Consequently, the bridge's width is 105 meters.

4 0
2 months ago
El área de una propiedad en metros cuadrados, mide 704/5. Se construye una casa que ocupa 5/6 del área total. La mitad del área
tester [12383]

Answer:

The remaining area available for construction is \frac{704}{60}\ m^{2}

Step-by-step analysis:

The inquiry in English reads

The total area of a property, measured in square meters, amounts to 704/5. A house is constructed occupying 5/6 of this area. Half of the leftover space is utilized for a terrace; thus, how much area remains for additional construction?

We know that

The total area is represented by the fraction 6/6

A house accounts for 5/6 of the entire area

Thus, the remaining area is (6/6)-(5/6)=1/6 of the overall area

If half of this leftover area is designated for a terrace

then

the terrace occupies (1/6)/2=1/12 of the total area

consequently,

The area remaining for construction is 1/12 of the total area

therefore

(\frac{1}{12})\frac{704}{5} =\frac{704}{60}\ m^{2}

8 0
2 months ago
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