A child who is trick-or-treating chooses a lollipop at random from a bowl of lollipops with mean weight 1.5 oz and standard devi
1 answer:
Answer:
The anticipated total weight of the child's lollipop and two chocolate bars is 5.5 oz.
Step-by-step explanation:
Normal probability distribution
When dealing with a normal distribution, we apply the z-score formula.
In a dataset featuring a mean of and a standard deviation of
, the z-score for a value X is calculated as:
The Z-score indicates the number of standard deviations a measurement is from the mean. After computing the Z-score, we utilize the z-score table to find the corresponding p-value for this score. This p-value represents the probability that the measured value is less than X, essentially the percentile of X. By subtracting the p-value from 1, we determine the likelihood that the measured value exceeds X.
Adding normal variables:
The overall mean is the sum of individual means.
We calculate the expected combined weight of the child's lollipop and the two chocolate bars.
The child's lollipop averages 1.5 oz
Two chocolate bars average 2 oz each
Combining one lollipop and two chocolate bars gives
The total average is 1.5 + 2*2 = 5.5 oz
Hence, the expected combined weight of the child's lollipop and the two chocolate bars is 5.5 oz.
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Step-by-step explanation:
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