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Lyrx
7 days ago
7

Grace invested $5,200 in an account paying an interest rate of 4.6% compounded daily. Assuming no deposits or withdrawals are ma

de, how much money, to the nearest dollar, would be in the account after 11 years?
Mathematics
1 answer:
lawyer [11.2K]7 days ago
8 0

Answer:

Step-by-step explanation:

This formula is applied when compounding isn’t continuous or occurs less frequently than annually:

A(t)=P(1+\frac{r}{n})^{(n)(t)} where P represents the initial amount invested, r signifies the interest rate as a decimal, n indicates the frequency of compounding per year, and t denotes the duration in years. For our scenario:

P = 5200,

r = 0.046,

n = 365, and

t = 11

A(t)=5200(1+\frac{.046}{365})^{(365)(11)} Consequently,

A(t)=5200(1+.000126)^{4015} A(t) = 5200(1.658408042) leads to

A(t) = $8623.72

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Answer:

The solution to this problem indicates that Hernry invested $18,000 in stocks and $6,000 in bonds.

Step-by-step explanation:

First, you need to multiply 6 by 3. The outcome is 18, meaning it is three times higher than the bond amount. Next, subtract $24,000 from $18,000, which gives you $6,000, representing the bond investment. Hence, it is three times less than the stocks as the question describes.

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According to a survey by Bankrate, of adults in the United States save nothing for retirement (CNBC website). Suppose that adult
tester [10823]

Complete Question

The complete question appears in the first uploaded image

Answer:

a) Yes, selecting 15 corresponds to a binomial experiment

b)

c)

d) P(r = 15) = 3.2768 *10^{-11}

Step-by-step explanation:

Regarding question a:

For an experiment to qualify as binomial

the trials have to be independent

each trial must yield one of two possible outcomes

Given that the selection of 15 individuals is random, we ascertain that the trials are independent and the outcomes are “either the individual saves for retirement or does not save for retirement.”

Therefore, we conclude that the selection of 15 people at random is indeed a binomial experiment.

In question b:

The probability that all selected adults do not save for retirement is mathematically modeled as

P(r = n) = ^nC_r * p^r * q^{n-r}

Here C signifies combination

r = 15 implies all selected adults

n refers to the population size equating to 15

From the problem, p = 0.20

and q can be calculated as

=>

=> q = 1 - p

Thus

P(r = 15) = ^{15}C_{15} * p^{15} * q^{15-15}

P(r = 15) = 3.2768 *10^{-11} Regarding question c:

The probability that exactly five of the selected adults do not save for retirement is mathematically modeled as

P(r = 5) = ^{15} C_5 * (0.20)^5 * (0.80)^{15}

P(r = 5) = 0.1032

In relation to question d:

The probability that at least one of the selected adults opts not to save for retirement can be mathematically expressed as

P(r \ge 1 ) = 1 - P (r = 0 )

P(r \ge 1 ) = 1 - [ ^{15} C _ 0 * (0.20)^{0} * (0.80 )^{15}]

P(r \ge 1 ) = 1 - 0.0352

P(r \ge 1 ) = 0.9648

4 0
23 days ago
In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each ty
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