Write square root 99 add square root 44 in the form A square root B where A and B are intergers

The 99% confidence interval for the actual mean difference between average mail-order and internet purchase amounts falls within [$(-31.82), $12.02].

Step-by-step clarification:

We know a random sample of 16 mail-order sales receipts shows a mean sale amount of $74.50 and a standard deviation of $17.25.

For internet sales, a random sample of 9 receipts gives a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal value utilized for constructing a 99% confidence interval for the true mean difference is given by;

                      P.Q.  =  

 ~

where,

= sample mean of mail-order sales = $74.50

= sample mean of internet sales = $84.40

= standard deviation for mail-order sales = $17.25

= standard deviation for internet sales = $21.25

= number of mail-order sales receipts = 16

= number of internet sales receipts = 9

Furthermore,  

 =   = 18.74

The actual mean difference between average mail-order and internet purchases is denoted by (

).

Thus, the 99% confidence interval for () is expressed as;

      = Here, the t critical value at the 0.5% significance level with 23 degrees of freedom is 2.807.           =

          = [$-31.82, $12.02]

Therefore, the 99% confidence interval for the true mean difference between average mail-order and internet purchases is [$(-31.82), $12.02].

B I hope this was helpful, though I'm not entirely certain.

Response:

When combining two fractions that each exceeds 1/2, their sum will invariably exceed 1.

Detailed breakdown: 1/2 + 1/2 = 1    

Since both fractions exceed this amount, it is evident that the sum must as well.

Examples: 2/3+3/4= 1 5/12        4/6+6/9= 1 1/3

Hope this adds clarity

Answer:

• 35,694
• 35,981
• 35,102

Step-by-step explanation:

If you compare numbers based on the hundreds digit, the digits to the left (thousands and ten-thousands) remain the same, while the hundreds digit differs.

This applies for any five-digit numbers structured like:

(3)(5)(not 7)(any digit)(any digit).

Digits to the right of the decimal point, as well as those in the tens and ones places, don't impact this comparison.

To determine the rates at which the inlet and outlet pipes fill and empty the reservoir, we remember that work done equals rate multiplied by time. Let’s denote the inlet rate as i and for the outlet pipe as 0. Therefore,
i(24) = 1
o(28) = 1
In this context, the '1' represents the total number of reservoirs, since the problem states the time needed for each pipe to either fill or empty a singular reservoir. Solving for rates yields:
i = 1/24 reservoirs/hour
o = 1/28 reservoirs/hour

Over the first six hours, the inlet pipe fills (1/24)(6) = 1/4 reservoirs and during the same period, the outlet pipe empties (1/28)(6) = 3/14 reservoirs. To calculate the net volume of the reservoir filled, we subtract the emptying total from the filling total:
1/4 - 3/14 = 1/28 reservoirs (note that if emptying exceeds filling, a negative value results. In such cases, treat that negative value as zero, indicating that the outlet rate surpasses the inlet rate, leading to an empty reservoir).
Now we need to find out how long it will take to fill up one reservoir since we’ve already partially filled 1/28 of it, after closing the outlet pipe. In simpler terms, we need to determine the time required for the inlet pipe to finish filling the remaining 27/28 of the reservoir. Fortunately, we have already established the filling rate for the inlet pipe, leading to the equation:
(1/24)t = 27/28
Solving for t gives us 23.14 hours. Remember to add the initial 6 hours to this result since the question seeks the total time. Thus, the final total is 29.14 hours.

Please ask me any questions you may have!