Suppose that 8 turns of a wire are wrapped around a pipe with a length of 60 inches and a circumference of 4​ inches, so that th

Answer:

The wire length is 32 inches.

Explanation:

According to the question,

The pipe's length = 60 inches

The pipe's circumference = 4 inches

Now,

The wire wraps around the pipe for 8 complete turns.

Now, with 2πr = 4, we find that

r = 2/π

Thus,

The radius, r = 2/π

The wire's length can be calculated as,

Length = Number of turns x Circumference of the pipe

So, length of wire = 8 x 4 = 32 inches.

Consequently, the wire length is 32 inches.

Explanation:

The given parameters are:

          Length of pipe = 60 inches

          Circumference of pipe = 4 inches

           Number of wire turns = 8

The wire spans from the bottom to the top of the pipe, translating to a distance of 60 inches in vertical length and 32 inches wrapped around the circumference. We can visualize the sides of the pipe overlapping each other, forming a large rectangle.

Thus, the rectangle's length is 60 inches.

Its width is set as .

                                   = 32

Let x denote the rectangle's diagonal; by applying Pythagoras' theorem to find the wire's length:

            = 3600 + 1024

               x =

                  = 68 inches.

Hence, we conclude that the wire length is 68 inches.