Q = mCΔT, in which Q = energy required, m = mass of the block, C = specific heat, ΔT = temperature change.
Utilizing the values provided;
Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.
The correct option is B.
<span>Conclusion: The door's weight results in a CCW torque which can be calculated as
Tccw = 145 N*3.13 m / 2.
You require a CW torque that balances this
Tcw = F*2.5 m*sin20</span>
Respuesta:
P_(bomba) = 98,000 Pa
Explicación:
Se nos proporciona;
h2 = 30m
h1 = 20m
Densidad; ρ = 1000 kg/m³
Primero, entendemos que la suma de las presiones en el tanque y la bomba es igual a la del boquilla,
Así, se puede expresar como;
P_(tanque)+ P_(bomba) = P_(boquilla)
Ahora, la presión se daría como;
P = ρgh
Y así,
ρgh_1 + P_(bomba) = ρgh_2
<ppor lo="" tanto="">
P_(bomba) = ρg(h_2 - h_1)
<pal sustituir="" los="" valores="" pertinentes="" obtenemos="">
P_(bomba) = 1000•9.8(30 - 20)
P_(bomba) = 98,000 Pa
</pal></ppor>
Answer:
The increase in pressure within the engine block of the car amounts to 1782.18 ATM.
Explanation:
Provided:
the volume change of water, ΔV = 9%
the bulk modulus for ice, K = 2 x 10⁹ N/m²
It is calculated using the bulk modulus formula;
so when the water freezes, the pressure increase in the automobile engine block is;
Thus, the final pressure increase inside the automobile engine block is 1782.18 ATM.
Initially, torque is defined as the product of force and distance. For the first force applied, the torque becomes zero since it acts at the hinge. Hence, the net torque is given by:
t = ( 12 N ) ( 0 m ) ( cos 30 ) + ( 12 N ) ( 1.68 m ) cos 45
t = 14.26 Nm represents the torque concerning the hinge
