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algol
1 month ago
9

A 75 kg skydiver can be modeled as a rectangular "box" with dimensions 20 cm * 40 cm * 180 cm. what is his terminal speed if he

falls feet first? use 0.8 for the drag coefficient.
Physics
1 answer:
kicyunya [3.2K]1 month ago
4 0

Terminal velocity=136.7 m/s

The formula for terminal velocity can be expressed as:

V= \sqrt{\frac{2 mg}{\rho a C}}

m= mass=75 kg

a= area=0.2 x 0.4=0.08 m²

ρ= density of air=1.23 kg/m³

C= drag coefficient =0.8

Thus, V= \sqrt{\frac{2 *75*9.8}{1.23*0.08*0.8}}

v= 136.7 m/s

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