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DochEvi
3 months ago
12

At room temperature what is the strength of the electric field in a 12-gauge copper wire (diameter 2.05 mm that is needed to cau

se a 2.75 a current to flow?
Physics
1 answer:
Maru [3.3K]3 months ago
6 0
Electric field strength can be calculated as resistivity of copper multiplied by the current density.
where
p= 1.72 x 10^-8 <span>ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
</span>First, we determine the current density:
current density = current / cross-sectional area
Calculating the cross-sectional area
cross-sectional area = pi.(d/2)^2;
cross-sectional area = 3.3 006x10-6 m^2
Substituting values gives us
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x10^2 A/m^2
Thus, electric field strength =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Resulting in electric field strength of 46.415 Volts/m.


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