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labwork
3 months ago
15

Jason swam 3 and one-half miles, then another 3 1/4th miles in one day. On the same day, Rachel swam 2 2/3rd miles, then another

4 and one-half miles. How many more miles did Rachel swim than Jason?
Mathematics
1 answer:
AnnZ [12.3K]3 months ago
7 0

Hello!

The answer is:

Rachel swam \frac{5}{12} miles, which is 0.42 miles more than Jason.

Why?

To determine how many additional miles Rachel swam compared to Jason, set up the equation:

Difference=RachelMiles-JasonMiles

Where,

Difference represents how many miles Rachel swam beyond Jason.

RachelMiles equals 2 2/3 plus 4.5 miles.

JasonMiles equals 3.5 plus 3 1/4 miles.

Remember to:

- Convert mixed numbers to improper fractions,

a\frac{b}{c}=a+\frac{b}{c}

- Add or subtract fractions and whole numbers.

a+\frac{b}{c}=\frac{ac+b}{c}

Given the data:

Jason's total distance:

JasonMiles=3\frac{1}{2}+3\frac{1}{4} =(3+\frac{1}{2})+(3+\frac{1}{4})\\\\JasonMiles=(3+\frac{1}{2})+(3+\frac{1}{4})=(\frac{(2)*(3)+1}{2})+(\frac{(3)*(4)+1}{4})\\\\JasonMiles=(\frac{(2)*(3)+1}{2})+(\frac{(3)*(4)+1}{4})=\frac{7}{2}+\frac{13}{4}\\\\JasonMiles=\frac{(7)*(4)+(2)*(13)}{8}=\frac{28+26}{8}=\frac{54}{8}\\\\JasonMiles=\frac{54}{8}=\frac{27}{4}miles

Rachel's total distance:

RachelMiles=2\frac{2}{3}+4\frac{1}{2}=(2+\frac{2}{3})+(4+\frac{1}{2})\\\\RachelMiles=(2+\frac{2}{3})+(4+\frac{1}{2})=(\frac{(2)*(3)+2}{3})+(\frac{(4)*(2)+1}{2})\\ \\RachelMiles=(\frac{(2)*(3)+2}{3})+(\frac{(4)*(2)+1}{2})=\frac{6+2}{3} +\frac{8+1}{2}\\\\RachelMiles=\frac{6+2}{3} +\frac{8+1}{2}=\frac{8}{3}+\frac{9}{2}\\\\RachelMiles=\frac{8}{3}+\frac{9}{2}=\frac{(8)*(2)+(3)*(9)}{(3)*(2)}\\\\RachelMiles=\frac{(8)*(2)+(3)*(9)}{(3)*(2)}=\frac{16+27}{6}=\frac{43}{6}miles

Substituting these values into the equation:

Difference=\frac{43}{6}-\frac{27}{4}=\frac{(43)*(4)-(6)*(27)}{24}\\\\Difference=\frac{(43)*(4)-(6)*(27)}{24}=\frac{172-162}{24}\\\\Difference=\frac{172-162}{24}=\frac{10}{24}=\frac{5}{12}miles=0.42miles

Therefore, Rachel swam 0.42 miles more than Jason.

Have a nice day!

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