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5 days ago

The curvature of the Tacoma Narrows Bridge in

Mathematics

1 answer:

tester [8.8K]5 days ago

4 0

Response:

The width of the arch measures 105 meters

Detailed explanation:

The function that describes the width of the arch is

f(x) = -0.016(x - 52.5)² + 45

where x denotes the horizontal distance from the left end of the arch or the width at its base

f(x) indicates the vertical height of the arch

According to the given quadratic equation, the vertex coordinates of the parabola are (52.5, 45).

The vertex coordinates indicate that

the arch's height is 45 meters

and half the horizontal span from the left end is 52.5 meters

Therefore, the bridge's total width is calculated as 2 times the half span from the left side, which is 2 × 52.5

resulting in 105 meters

Consequently, the bridge's width is 105 meters.

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22 days ago

Terrence walks at a pace of 2 mi/h to the theater and watches a movie for 2 hours and 15 min he rides a bus back home at 40 mi/h

zzz [9093]

Solution:

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