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Minchanka
1 month ago
9

johanna prepares a mixture of salad mixed with mayonnaise carrots cucumber lettuce and cheese. what type of mixture divine salad

is? why do you think so?​
Mathematics
1 answer:
tester [12.3K]1 month ago
5 0

Answer:

Johanna creates a combination of salad featuring mayonnaise, carrots, cucumber, lettuce, and cheese. What classification of mixture does this divine salad represent? What makes you think so?

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Circle 1 has center (−4, −7) and a radius of 12 cm. Circle 2 has center (3, 4) and a radius of 15 cm.
Svet_ta [12734]
Answer with explanation: Given that Circle 1 has a center at (−4, −7) and a radius of 12 cm, while Circle 2's center is at (3, 4) with a radius of 15 cm. Two circles are similar if one can be transformed and scaled to fit over the other, creating identical circles. The circles qualify as similar because the transformation rule (x,y) → (x+7,y+11) can be applied to Circle 1, followed by dilation using a scale factor of 5/4. Since Circle 1's center is at (-4,-7), we translate it to (3,4) through (-4+7,-7+11). With Circle 1 having a radius of 12 and Circle 2 having 15 cm, we denote the scale factor as k.
7 0
20 days ago
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Solve X-9+2wx=y for x
tester [12383]
X - 9 + 2wx = y Add 9 to both sides of the equation to isolate terms. Next, you get x + 2wx = y + 9. After that, factor out x to obtain x (1 + 2w) = y + 9. Lastly, divide every term by (1 + 2w) yielding x = (y + 9) / (1 + 2w).
8 0
1 month ago
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Minato drove 390 miles. Part of the drive was along local roads, where his average speed was 20 mph, and the rest was along a hi
lawyer [12517]

Answer:

45 millas.

Explicación paso a paso:

Dado que la:

Distancia total recorrida = 390 millas

Tiempo total = 8 horas

Designando la distancia recorrida por la vía local como L

y la distancia recorrida por la carretera como H

Por la vía local,

La Velocidad = distancia/ tiempo

20 = L / T

T = L /20.... (1)

Por la carretera,

Distancia recorrida H = 390 - L

Sea el tiempo = t

La Velocidad = distancia/tiempo

60 = (390 - L)/t

t = ( 390 - L)/60

Pero el tiempo total = T + t

<pEs decir

8 = L/20 + (390 - L)/60

<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz

480 = 2L + 390

<pAgrupamos los términos semejantes

2L = 480 - 390

2L = 90

L = 90/2

L = 45 millas.

<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas

4 0
1 month ago
You’re working in a pharmacy, and are making a table to help with dosage amounts for a certain drug. The recommended dosage is 4
lawyer [12517]

Answer: Children who weigh 10 pounds require 12 teaspoons, those at 15 pounds need 18 teaspoons, and for 30 pounds, it is necessary to have 36 teaspoons.

Step-by-step explanation:

We have a recommended dose of 40 mg per 2.2 pounds of weight, given in three doses throughout the day every 8 hours.

Thus, for a single pound, the daily required dosage is calculated as \dfrac{40}{2.2}=18.18\ ml.

Each individual dose corresponds to \dfrac{18.18}{3}=6.06\ ml of the drug.

This means for one pound, the dosage needed per dose is 6.06 ml.

Thus, for 10 pounds, the calculation is 10 x 6.06 ml = 60.6 ml

To convert ml to teaspoons, knowing that 1 teaspoon equals 5 ml, we find: (60.6 ml ÷ 5) = 12.12 ≈ 12 teaspoons.

For a weight of 15 pounds, the drug requirement is 15 x 6.06 ml = 90.9 ml.

This translates to (90.9 ml ÷ 5) = 18.18 ≈ 18 teaspoons.

For the weight of 30 pounds, it is calculated as 30 x 6.06 ml = 181.8 ml.

Converting this gives us (181.8 ml ÷ 5) = 36.36 ≈ 36 teaspoons.

Therefore, children weighing 10 pounds need 12 teaspoons, those at 15 pounds require 18 teaspoons, and those at 30 pounds need 36 teaspoons.

7 0
1 month ago
A. Consider the following algorithm segment: for i := 1 to 4, for j := 1 to i, [Statements in body of inner loop. None contain b
tester [12383]

Answer:

(a) 4i iterations

(b) "i × n" iterations

Step-by-step explanation:

(a) The provided algorithm segment shows:

for i:= 1 to 4, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

The inner loop executes i times while the outer loop completes 4 cycles.

The inner loop’s total execution when the full algorithm runs is:

= i × 4

= 4i iterations

(b) In the given algorithm segment;

for i:= 1 to n, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

where n denotes a set of positive integers.

<pthe inner="" loop="" also="" runs="" for="" times="" and="" the="" outer="" times.=""><pthus the="" total="" iterations="" of="" inner="" loop="" for="" entire="" algorithm="" is:="">

= i × n

= "i × n" iterations

</pthus></pthe>
6 0
1 month ago
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