For the 7:30 show time, 140 movie tickets were sold. Receipts from the $13 adult tickets and the $10 senior tickets totaled $1,6

Answer:

Confidence Interval

Lower Limit = $4,233.3

Upper Limit = $4,766.7

With 95% certainty, SoftBus can anticipate that the average profit per customer will fall within the range of $4,233.30 to $4,766.7, based on the provided sample data.

Step-by-step explanation:

The z-score corresponding to 95% is 1.96

             Profit         Mean      Square Root

                           Difference    of MD

P1        $5,000       $500        $250,000

P2         4,500          0              0

P3         4,000       -500         $250,000

Total $13,500                        $500,000

Mean $4,500 ($13,500/3)    $166,667 ($500,000/3)

Standard Deviation = Square root of $166,667 = 408.2

Margin of error = (z-score * standard deviation)/n

= (1.96 * 408.2)/3

= 266.7

= $266.7

Confidence Interval = Sample mean +/- Margin of error

= $4,500 +/- 266.7

Lower Limit = $4,233.3 ($4,500 - $266.7)

Upper Limit = $4,766.7 ($4,500 + $266.7)

Answer:

You need to multiply the denorminator both sides in order to form x note the subject:

Response:

Detailed explanation:

a) this situation has a two-tailed test

The critical value is found using the t distribution table.

α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Consulting 0.975 with df 10

The critical value obtained is 2.228

b) α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Consulting 0.975 with df 20

The critical value obtained is 2.086

c) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Consulting 0.995 with df 20

The critical value obtained is 2.845

d) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Consulting 0.995 with df 60

The critical value obtained is 2.660

e) 1 - α = 1 - 0.01 = 0.99

Consulting 0.99 with df 10

The critical value obtained is 2.764

f) 1 - α = 1 - 0.025 = 0.975

Consulting 0.975 with df 5

The critical value obtained is 2.571