Response:
0; 10; 20
Detailed explanation:
x serves as the independent variable
y functions as the dependent variable
the value of y relies on x
a) What is the independent variable value that makes the function result in −6
y=0.3x−6
-6 = 0.3x-6
0=0.3x
x = 0
Hence, when the independent variable is 0, the function yields -6.
b) What is the independent variable value for which the function equals −3
y=0.3x−6
-3 = 0.3x-6
0.3x = -3+6
0.3x = 3
x = 3/0.3
x = 10
Thus, if the independent variable is 10, the function will give -3.
c) What independent variable value results in a function of 0.
y=0.3x−6
0=0.3x-6
6 = 0.3x
x = 6/0.3
x = 20
Therefore, for an independent variable of 20, the function results in 0.
When rounding 243.875: to the nearest tenth, it becomes 243.9; to the nearest hundredth, it is 243.88; to the nearest ten, it rounds down to 240; and to the nearest hundred, it rounds down to 200. The general rule in rounding states that if the decimal is less than 5, the number remains the same; if it is 5 or more, you round up.
Answer:
78/4
Step-by-step explanation:
this seems correct
Answer:
0.40
Step-by-step explanation:
The percentage of members who engage only in long-distance running is 8%
Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08
The percentage of members who participate exclusively in field events is 32%
Thus, the probability of a member competing only in field events is P(B) = 0.32
The percentage of members acting as sprinters is 12%
So, the probability that a member is a sprinter is P(C) = 0.12
We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:
P(A or B) = P(A) + P(B)
Substituting the known values results in:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40
