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14 days ago

Colton has a stone paperweight composed of a triangular pyramid on top of a triangular prism with the dimensions shown below. Us

e the drop-down menus to explain how to determine the volume of the paperweight. Needdddd major hellllpppp pleaseeee!!!!! 40 points!!!

Mathematics

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A certain temperature measurement is performed 500 times. The mean value is 0 deg F and the standard deviation is 1 deg F. Assum

Svet_ta [12734]

Response:

477

Detailed explanation:

Provided information:

Number of trials (n) = 500

Mean (m) = 0

Standard deviation (s) = 1

how many readings fall within +/- 2.000 deg F of the mean value

Mean of 0 and standard deviation of 1

P(-2 ≤ x ≤ 2)

Utilizing the Z probability calculator:

P(x ≤ 2) = 0.97725;

P(x ≤ - 2) = 0.02275

Thus:

P(x ≤ 2) - P(x ≤ - 2) = 0.97725 - 0.02275 = 0.9545

Accordingly, number of readings in 500 trials:

0.9545 multiplied by 500 equals 477.25

≈ 477 values

6 0

1 month ago

Jessica is asked to write a quadratic equation to represent a function that goes through the point (8, –11) and has a vertex at

PIT_PIT [12445]

the answer is c. I completed the review

5 0

2 months ago

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Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3). Round your answer to the ne

tester [12383]

Answer: 20 units

Step-by-step explanation:

The formula for calculating the distance between two coordinates P(a,b) and Q(c,d) is as follows:-

$PQ=\sqrt{(d-b)^2+(c-a)^2}$

Initially provided: The coordinates of the quadrilateral's vertices are C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

The distance between vertices C (−2, 1) and D (2, 4) is as follows:-

$CD=\sqrt{(4-1)^2+(2-(-2))^2}\\\\\Rightarrow\ CD=\sqrt{(3)^2+(4)^2}\\\\\Rightarrow\ CD=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ CD=5\text{ units}$

Distance between points D (2, 4) and E (5, 0) is calculated as:-

$DE=\sqrt{(4-0)^2+(2-5)^2}\\\\\Rightarrow\ DE=\sqrt{(4)^2+(-3)^2}\\\\\Rightarrow\ DE=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ DE=5\text{ units}$

Distance between coordinates E (5, 0) and F (1, −3) is given by:-

$EF=\sqrt{(-3-0)^2+(1-5)^2}\\\\\Rightarrow\ EF=\sqrt{(-3)^2+(-4)^2}\\\\\Rightarrow\ EF=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ EF=5\text{ units}$

Distance from C (−2, 1) to F (1, −3) is as follows:-

$FC=\sqrt{(-3-1))^2+(1-(-2))^2}\\\\\Rightarrow\ FC=\sqrt{(-4)^2+(3)^2}\\\\\Rightarrow\ FC=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ FC=5\text{ units}$

The total perimeter of the quadrilateral is calculated as = CD + DE + EF + FC

$=5+5+5+5=20\text{ units}$

3 0

2 months ago

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