Response:
Detailed explanation:
The final result is 3 /8/33.
step by step breakdown
Initially, we write:
x
=
3
.
¯¯¯¯
24
After that, we will multiply each side by
100
leading to:
100
x
=
324
.
¯¯¯¯
24
Subsequently, we will subtract the first equation from the second equation:
100
x
−
x
=
324
.
¯¯¯¯
24
−
3
.
¯¯¯¯
24
We can then solve for
x
in the following manner:
100
x
−
1
x
=
(
324
+
0
.
¯¯¯¯
24
)
−
(
3
+
0
.
¯¯¯¯
24
)
(
100
−
1
)
x
=
324
+
0
.
¯¯¯¯
24
−
3
−
0
.
¯¯¯¯
24
99
x
=
(
324
−
3
)
+
(
0
.
¯¯¯¯
24
−
0
.
¯¯¯¯
24
)
99
x
=
321
+
0
99
x
=
321
99
x
99
=
321
99
99
x
99
=
3
×
107
3
×
33
x
=
3
×
107
3
×
33
x
=
107
33
Next, we convert this improper fraction to a mixed numeral:
x
=
107
33
=
99
+
8
33
=
99
33
+
8
33
=
3
+
8
33
=
3
8
33
3
.
¯¯¯¯
=
3
8
33
Answer:
Approximately 59 stacked cups.
Step-by-step explanation:
We have the following measurements:
Height of one cup = 12.5 cm,
Height of two cups stacked = 14 cm,
Height of three cups stacked = 15.5 cm,
...and so on.
This situation can be described by an arithmetic sequence,
12.5, 14, 15.5,....
The first term is defined as a = 12.5,
with a common difference of d = 1.5 cm.
Thus, the height of x stacked cups is given by

As per the problem,
h(x) = 200
⇒ 1.5x + 11 = 200
⇒ 1.5x = 189
⇒ x = 59.3333333333 ≈ 59.
Therefore, you will need approximately 59 stacked cups.
Answer:
118.2°
Step-by-step explanation:
Dos líneas paralelas x e y son cortadas por la transversal w (ver el diagrama adjunto).
Se forman 8 ángulos (denominados 1, 2, 3, 4, 5, 6, 7 y 8).
Los ángulos 1 y 6 son ángulos del mismo lado cuando dos líneas paralelas x e y son cortadas por la transversal w.
Dos ángulos del mismo lado son suplementarios (suman 180°). Esto significa

Dado
por lo que

Answer:
Question 13: For age groups y=1 and y=1.3, the response time is 8 microseconds.
Question 14: The club experienced losses between 11.28 and 4.88 years.
Step-by-step explanation:
Question 13:
The equation that gives the response rate R of 8 microseconds can be expressed as

Upon graphing this, we determine the solutions to be

We consider only positive values of y applicable in real-life scenarios.
Thus, the response is 8 microseconds solely for the age groups y=1 and y=1.3.
Question 14:
The football club incurs losses when 
Or

Graphing this inequality reveals the solutions to be
and 
As only positive values for t are relevant in practical situations, we accept the second solution.
Hence, the club faced losses during the years 