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nalin
1 month ago
11

You are watering a garden. The height h (in feet) of water spraying from the garden hose can be modeled by h(x)=−0.1x2+0.7x+3, w

here x is the horizontal distance (in feet) from where you are standing. You raise the hose so that the water hits the ground 1 foot farther from where you are standing. Write a function that models the new path of the water.
Mathematics
1 answer:
lawyer [12.5K]1 month ago
3 0

Answer:

g(x) = -0.1x^2 + 0.5x + 3.6

Step-by-step explanation:

Given

h(x) = -0.1x^2 + 0.7x + 3

Required

Find the updated function

The problem specifies that the water should land 1 ft further away.

This means we need to use x + 1

Consequently, in the initial function, we will replace x with x + 1 in h(x) = -0.1x^2 + 0.7x + 3

Thus, we obtain:

h(x + 1) = -0.1(x + 1)^2 + 0.7(x + 1) + 3

Expand the Parenthesis

h(x + 1) = -0.1(x + 1)(x + 1) + 0.7(x + 1) + 3

h(x + 1) = -0.1(x^2+2x+1) + 0.7(x + 1) + 3

h(x + 1) = -0.1x^2-0.2x-0.1 + 0.7x + 0.7 + 3

Combine Like Terms

h(x + 1) = -0.1x^2-0.2x + 0.7x + 0.7 + 3-0.1

h(x + 1) = -0.1x^2 + 0.5x + 3.6

The resulting function is:

g(x) = h(x + 1) = -0.1x^2 + 0.5x + 3.6

g(x) = -0.1x^2 + 0.5x + 3.6

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Answer:0.246 ft/s

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V = s/t... equation 1

S = distance the worker travels while pulling the rope = 10 ft

V = worker's velocity = 2 ft/s

T = time it takes for the worker to cover 10 ft = the same time the load takes to rise = 5 seconds

Using Pythagorean theorem to find the distance from the pulley to the new position of the worker

Square root of (40^2 + 10^2) = 41.23 ft

Distance covered by load = D = 41.23 - 40

= 1.23 ft

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Substituting D and t into equation 2 gives us

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Step-by-step explanation:

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Respuesta:

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Explicación paso a paso:

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Por lo tanto, debemos calcular inicialmente la probabilidad de que el número obtenido sea par.

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Para encontrar la probabilidad de obtener un número par mayor que 10:

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Answer:

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3. Substitution Property of Equality.

4. Transitive Property of Equality.

Step-by-step explanation:

Given: CD = EF and AB = CE

To Show: AB = DF

Following the steps outlined:

1. CD + DE = EF + DE by the (addition) Property of Equality.

This shows that the same value has been added to both sides of the equation.

2. CE = CD + DE and DF = EF + DE through (segment addition).

This indicates that CE and DF are segments, and the length of any segment equals the total of its parts.

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