Answer:
The price amounts to $9.70 per kilogram.
Step-by-step explanation:
This can be resolved using the rule of three.
In a rule of three scenario, the first step involves determining how the values are related, whether directly or inversely.
A direct relationship implies that when one measure increases, the corresponding measure also increases. In this case, cross multiplication serves as the method for the rule of three.
Alternatively, an inverse relationship indicates that an increase in one measurement causes a decrease in the other. In this scenario, line multiplication applies.
Here, the relationship is between the weight of the cheese and its cost. As the weight rises, so does the expense, representing a direct proportion.
Solution:
According to the problem, cheese is priced at $4.40 per pound. Given that each kg equals 2.2 pounds, we can deduce how many kg correspond to one pound.
1 pound - x kg
2.2 pounds - 1 kg


kg
Given that cheese costs $4.40 for a pound, and there are 0.45 kg in one pound, we calculate the cost for 1 kg.
$4.40 - 0.45 kg
$x - 1 kg



The price is $9.70 per kilogram.
Answer:
The standard ticket price was $12.
Step-by-step explanation:
Let’s denote
the normal ticket price, which would total
if she had purchased tickets for that amount.
However, since Holly received a $4 discount on each ticket, her cost for one ticket became
and with 23 tickets, her total cost was

amounting to $184; thus, we conclude

we will solve this equation as follows:





Therefore, the regular price amounted to $12.
To illustrate 1 hundredth (or 1%) on a grid consisting of 100 units, shade only 1 unit. In contrast, to illustrate 1 tenth (or 10%), you would shade 10 units. A visual representation of the grid would be helpful for further explanation.
According to the details provided in the question, m∠2 = 41°, m∠5 = 94°, and m∠10 = 109°. Since ∠2 is congruent to ∠9 (alternate interior angles), we establish that m∠2 = m∠9 = 41°. Utilizing the angle sum property, we have m∠8 + m∠9 + m∠10 = 180°, leading to m∠8 + 41 + 109 = 180°. Thus, m∠8 equates to 30°. From the triangle's angle sum, m∠2 + m∠7 + m∠8 = 180°, resulting in 41 + m∠7 + 30 = 180°. Consequently, m∠7 calculates to 109°. Also, m∠6 + m∠7 = 180°, so m∠6 comes to 71°. Given that m∠5 + m∠4 = 180°, we have m∠4 = 86°. Lastly, using the triangle angle sum theorem again, m∠4 + m∠3 + m∠9 = 180°, so m∠3 calculates to 53°. Thus, through the angle relationship, m∠1 + m∠2 + m∠3 = 180°, leading to m∠1 = 86°.