Answer: We start with equation 1
x=64/3
Next, we solve equation 2
y=125/3
Now, we combine equations 1 and 2
y-x=125/3 -64/3
=61/3
Step-by-step explanation:
Answer:
C. 5 degrees of freedom for the numerator and 114 for the denominator
Step-by-step explanation:
Analysis of variance (ANOVA) is utilized to examine the variations among group means within a sample.
The sum of squares represents the cumulative square of variation, which refers to the deviation of each individual value from the grand mean.
Assuming there are 
groups and each group contains 
individuals, the variation can be calculated using the following formulas:
This also has the property
The numerator's degrees of freedom in this case is given by 
where k = 6 represents the number of groups.
The denominator's degrees of freedom in this scenario is indicated by 
.
The total degrees of freedom would be 
.
Thus, the appropriate answer would be 5 degrees of freedom for the numerator and 119 degrees of freedom for the denominator.
C. 5 numerator and 114 denominator degrees of freedom
<span><span>1. </span>We have two boxes with weights:
=> 9.4 lb and 62.6 lb.
To find a rough estimate of their total weight, we will round and use compatible numbers.
For 9.4 lbs, rounding gives us 9 lbs
And for 62.6 lbs, it rounds to 63 lbs
=> Adding these two rounded numbers yields:
=> 9 + 63
=> 72, the estimated total is 72.
Let’s verify if this is close to the actual weight
=> 9.4 + 62.6
=> 72</span>
The initial score was 80, and there was a wrongfully deducted 5 points. This indicates that any result equating to 85 is the correct outcome.
80 + 5 = 85
80 - (-5) = 85
Response: Therefore, the fraction of times heads appeared out of the entire tosses is 0.583
Detailed explanation:
Considering the following:
Total number of tosses for the coin = 60
Total occurrences of heads = 35
Calculated proportion of heads landed:
Total occurrences of heads / total number of coin tosses
Calculated head landing proportion:
= 35 / 60 = 7 / 12 = 0.5833
