What value is equivalent to 2 × 3 + 4 − 62? A) -26 B) -22 C) -2 D) 10

Answer:

a. 80 students

b. 92 students

Step-by-step explanation:

Designate arts students as A and dance students as D.

Thus, we have,[['[TAG_14]]

n(A) = 35

n(D) = 57

Required

To determine n(A or D)

For (a):

We find that:

n(A and D) = 12

The calculation for n(A or D) is as follows:

n(A or D) = n(A) + n(D) - n(A and D)

n(A or D) = 35 + 57 - 12

n(A or D) = 80

b. Given the details

n(A and D) = 0 since no students are enrolled in both classes as indicated in (a)

Using the same formula as in (a).

n(A or D) = n(A) + n(D) - n(A and D)

n(A or D) = 35 + 57 - 0

n(A or D) = 92

For Chris, the calculation for his monthly telephone expense is as follows:

Where "x" denotes each minute used.

Given that Chris can afford a bill of $86, we have:

The total minutes of usage must not exceed 500 per month. Consequently, the viable choice is option C.

Answer:

Option C

If you are referring to (r+5)/mn, then:

Answer:

  (1/10)∛100 ≈ 0.4642

Step-by-step explanation:

For a cubic shape with volume V, the edge length is defined as...

  s = ∛V

and the surface area is given by...

  A = 6s² = 6V^(2/3)

The area-to-volume ratio is therefore...

  r1 = A/V = 6V^(2/3)/V = 6V^(-1/3)

When the volume V is increased by a factor of 10, the new area-to-volume ratio becomes...

  r2 = 6(10V)^(-1/3)

Consequently, the change factor for the ratio is...

  r2/r1 = (6(10V)^(-1/3))/(6V^(-1/3)) = 10^(-1/3) = (1/10)∛100

The change in surface area per unit volume results in a factor of (∛100)/10.

___

Example

For a cube with side length 2, the corresponding volume equals 2³ = 8, with a surface area of 6·2² = 24. The resulting area-to-volume ratio is 24/8 = 3.

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The area-to-volume ratio changed by a factor of (0.3∛100)/3 = (∛100)/10, as previously noted.

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As a fraction, 2.161616 is represented as 2 161616/1000000, and when simplified, it becomes 2 10101/62500.