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jolli1
1 month ago
15

A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s

in the air, which equation models the height of the ball correctly? Assume that acceleration due to gravity is –16 ft/s2.
Mathematics
1 answer:
zzz [12.3K]1 month ago
6 0
To find the height equation for the soccer ball's trajectory, we start with the acceleration due to gravity of g=9.81 m/s². Converting this gives us approximately 32.18 ft/s², rounded to 32 ft/s². The height formula is h = -g/2 * t² + vt + h0. Setting t=0 and h=0, we deduce that h0=0. Thus h=-16t² + vt applies. Given that the ball reaches 50 ft in 2.5 s, it reaches 25 ft in 1.25 s. Now, using 25=-16(1.25)² + v(1.25), we find velocity v=50/1.25, which simplifies to 40. Therefore, the height equation is h = -16t² + 40t.
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