Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with

100 plus 70 equals 170

170 divided by 10 equals 17

That makes 17 trains of 10 cubes

To solve the equation 3x^2-4x=0 graphically, Amber will begin by plotting the graph of y=4x, and the x-coordinate points where the graphs intersect will provide the solutions.

The solution for y is y = \frac{a}{3(3 + x)}

Answer:

It could either be 455 or 680, based on assumptions.

Step-by-step explanation:

Assuming the three choices are distinct, we can calculate...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to create the pizza.

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In the case where two or more of the toppings may be identical, this would lead to...

  2(15C2) + 15C1 = 2·105 + 15 = 225

additional combinations, resulting in a grand total of...

  455 + 225 = 680

unique pizza varieties.

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There is a multiplication factor of 2 for the two-topping selections, since it allows for variations like double anchovies and tomatoes or double tomatoes and anchovies when the topping choices are anchovies and tomatoes.

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nCk = n!/(k!(n-k)!)

Answer:

175/3 or 58.333...

Step-by-step explanation:

This problem can be complex, but I'll simplify it. I apologize for the challenges involved in formatting fractions correctly. To ensure accuracy, I've added several parentheses that may seem unnecessary.

Let d denote the distance between the two cities.

The time it takes can be expressed as d/r, where r represents the speed; thus, from B to NY, it is d/50.

In the same manner, from NY to B, it's d/70.

The average velocity can be determined as 2d divided by the sum of d/50 and d/70, representing the average time.

Next, eliminate d from the equation to reach (d/d)*2/(1/50+1/70).

Now, you can multiply by the Least Common Multiple (LCM) over itself, which is 350/350.

The result after performing this calculation will yield 700/12, equating to 58.333...(This is how you would enter it into your RSM browser) I hope this clarification is useful. My apologies for the delay.