Given ΔSTU and ΔDEF, what is m∠U ?

Answer:

a.

b.

c.

d.

Step-by-step explanation:

There are four desktop computers and two laptops.

On a specific day, we will set up 2 of these computers.

To find:

a. What is the probability that both selected computers are laptops?

b. What is the probability that both computers are desktops?

c. What is the probability that at least one computer is a desktop?

d. What is the probability that at least one of each type of computer is included?

Solution:

Using the probability formula for event E:

a. The number of successful outcomes for both computers being laptops = = 1

Total possible outcomes = 15

The needed probability is .

b. The successful outcomes for both being desktop computers =

Total possible outcomes = 15

The required probability is .

c. For at least one desktop:

Two scenarios exist:

1. 1 desktop and 1 laptop:

Successful outcomes =

2. Both are desktops:

Successful outcomes =

Total successful outcomes = 8 + 6 = 14

The needed probability is .

d. 1 desktop and 1 laptop:

Successful outcomes =

Total outcomes = 15

The required probability is .

The equation for the problem is ≤

Hope this is useful!

Response:

The data shows skewness, with the minimum amount of crackers in a pack being 7

Detailed explanation:

Hello,

Firstly, the question lacks completeness due to missing information from the box plot, which I have provided to assist you in answering your inquiry.

Considering the details from the attached image, a symmetric distribution would be centered evenly, but that is not the case here.

The image indicates a positive skew, with the lowest count recorded as 7.

Answer: The option that is correct is

(C) T0,2(x, y)∘ R0, 270°.

Step-by-step explanation: We need to choose the transformation rule that defines how rectangle PQRS is transformed into P''Q''R''S''.

Observing the graph, we can identify that

the points of rectangle PQRS are P(-3, -5), Q(-2, -5), R(-2, -1) and S(-3, -1).

Conversely, the vertices of rectangle P''Q''R''S'' are P''(-5, 5), Q''(-5, 4), R''(-1, 4) and S(-1, 5).

The rectangle PQRS resides in Quadrant III while P''Q''R''S'' is located in Quadrant II,indicating that the rotation could either be 90° clockwise or 270° counterclockwise around the origin.

Among the provided choices, there is no 90° rotation available, hence we will consider the 270° counterclockwise rotation around the origin.

After executing this rotation, the points transform based on the rule

(x, y) ⇒ (y, -x).

Thus, the vertices of the resulting rectangle P'Q'R'S', after a 270° counterclockwise rotation around the origin, become

P(-3, -5) ⇒ P'(-5, 3),

Q(-2, -5) ⇒ Q'(-5, 2),

R(-2, -1) ⇒ R'(-1, 2),

S(-3, -1) ⇒ S'(-1, 3).

To align the vertices of P'Q'R'S' with those of P''Q''R''S'', we must add 2 units to the y-coordinate of all vertices , leading to

P'(-5, 3) ⇒ P''(-5, 3+2) = P''(-5, 5),

Q'(-5, 2) ⇒ Q''(-5, 2+2) = Q''(-5, 4),

R'(-1, 2) ⇒ R''(-1, 2+2) = R''(-1, 4),

S'(-1, 3) ⇒ S''(-1, 3+2) = S''(-1, 5).

Thus, the required transformation rule becomes

a rotation through 270° counterclockwise around the origin coupled with a translation of (x, y) ⇒ (x, y+2).

Since rigid transformations are documented from right to left, option (C) is indeed correct.